牛客 子数组最大异或和
题目大意:
略。
分析:
求出前缀异或和后这道题就是"LeetCode 数组中两个数的最大异或值"的升级版,由于有正有负,所以第一位符号位要单独讨论.
PS:当只有一个数的时候也要单独讨论
代码如下:
1 #include <bits/stdc++.h> 2 using namespace std; 3 4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0); 5 #define Rep(i,n) for (int i = 0; i < (int)(n); ++i) 6 #define For(i,s,t) for (int i = (int)(s); i <= (int)(t); ++i) 7 #define rFor(i,t,s) for (int i = (int)(t); i >= (int)(s); --i) 8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i) 9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i) 10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i) 11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i) 12 13 #define pr(x) cout << #x << " = " << x << " " 14 #define prln(x) cout << #x << " = " << x << endl 15 16 #define LOWBIT(x) ((x)&(-x)) 17 18 #define ALL(x) x.begin(),x.end() 19 #define INS(x) inserter(x,x.begin()) 20 #define UNIQUE(x) x.erase(unique(x.begin(), x.end()), x.end()) 21 #define REMOVE(x, c) x.erase(remove(x.begin(), x.end(), c), x.end()); // 删去 x 中所有 c 22 #define TOLOWER(x) transform(x.begin(), x.end(), x.begin(),::tolower); 23 #define TOUPPER(x) transform(x.begin(), x.end(), x.begin(),::toupper); 24 25 #define ms0(a) memset(a,0,sizeof(a)) 26 #define msI(a) memset(a,0x3f,sizeof(a)) 27 #define msM(a) memset(a,-1,sizeof(a)) 28 29 #define MP make_pair 30 #define PB push_back 31 #define ft first 32 #define sd second 33 34 template<typename T1, typename T2> 35 istream &operator>>(istream &in, pair<T1, T2> &p) { 36 in >> p.first >> p.second; 37 return in; 38 } 39 40 template<typename T> 41 istream &operator>>(istream &in, vector<T> &v) { 42 for (auto &x: v) 43 in >> x; 44 return in; 45 } 46 47 template<typename T> 48 ostream &operator<<(ostream &out, vector<T> &v) { 49 Rep(i, v.size()) out << v[i] << " \n"[i == v.size() - 1]; 50 return out; 51 } 52 53 template<typename T1, typename T2> 54 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) { 55 out << "[" << p.first << ", " << p.second << "]" << "\n"; 56 return out; 57 } 58 59 inline int gc(){ 60 static const int BUF = 1e7; 61 static char buf[BUF], *bg = buf + BUF, *ed = bg; 62 63 if(bg == ed) fread(bg = buf, 1, BUF, stdin); 64 return *bg++; 65 } 66 67 inline int ri(){ 68 int x = 0, f = 1, c = gc(); 69 for(; c<48||c>57; f = c=='-'?-1:f, c=gc()); 70 for(; c>47&&c<58; x = x*10 + c - 48, c=gc()); 71 return x*f; 72 } 73 74 template<class T> 75 inline string toString(T x) { 76 ostringstream sout; 77 sout << x; 78 return sout.str(); 79 } 80 81 inline int toInt(string s) { 82 int v; 83 istringstream sin(s); 84 sin >> v; 85 return v; 86 } 87 88 //min <= aim <= max 89 template<typename T> 90 inline bool BETWEEN(const T aim, const T min, const T max) { 91 return min <= aim && aim <= max; 92 } 93 94 typedef unsigned int uI; 95 typedef long long LL; 96 typedef unsigned long long uLL; 97 typedef vector< int > VI; 98 typedef vector< bool > VB; 99 typedef vector< char > VC; 100 typedef vector< double > VD; 101 typedef vector< string > VS; 102 typedef vector< LL > VL; 103 typedef vector< VI > VVI; 104 typedef vector< VB > VVB; 105 typedef vector< VS > VVS; 106 typedef vector< VL > VVL; 107 typedef vector< VVI > VVVI; 108 typedef vector< VVL > VVVL; 109 typedef pair< int, int > PII; 110 typedef pair< LL, LL > PLL; 111 typedef pair< int, string > PIS; 112 typedef pair< string, int > PSI; 113 typedef pair< string, string > PSS; 114 typedef pair< double, double > PDD; 115 typedef vector< PII > VPII; 116 typedef vector< PLL > VPLL; 117 typedef vector< VPII > VVPII; 118 typedef vector< VPLL > VVPLL; 119 typedef vector< VS > VVS; 120 typedef map< int, int > MII; 121 typedef unordered_map< int, int > uMII; 122 typedef map< LL, LL > MLL; 123 typedef map< string, int > MSI; 124 typedef map< int, string > MIS; 125 typedef multiset< int > mSI; 126 typedef multiset< char > mSC; 127 typedef set< int > SI; 128 typedef stack< int > SKI; 129 typedef stack< char > SKC; 130 typedef deque< int > DQI; 131 typedef queue< int > QI; 132 typedef priority_queue< int > PQIMax; 133 typedef priority_queue< int, VI, greater< int > > PQIMin; 134 const double EPS = 1e-8; 135 const LL inf = 0x7fffffff; 136 const LL infLL = 0x7fffffffffffffffLL; 137 const LL mod = 1e9 + 7; 138 const int maxN = 1e5 + 7; 139 const LL ONE = 1; 140 const LL evenBits = 0xaaaaaaaaaaaaaaaa; 141 const LL oddBits = 0x5555555555555555; 142 143 class Trie { 144 public: 145 Trie* nxt[2]; 146 147 Trie() { 148 nxt[0] = nxt[1] = NULL; 149 } 150 151 void insert(string word) { 152 Trie* p = this; 153 Rep(i, word.size()) { 154 int key = word[i] - '0'; 155 156 if(p->nxt[key] == NULL) { 157 p->nxt[key] = new Trie(); 158 } 159 p = p->nxt[key]; 160 } 161 } 162 163 int solve(string word) { 164 int ret = 0; 165 LL mask = (ONE << 31); 166 167 Trie* p = this; 168 int key = word[0] - '0'; 169 if(p->nxt[key] == NULL) { // 符号位要单独讨论 170 ret |= mask; 171 key = !key; 172 } 173 mask >>= 1; 174 p = p->nxt[key]; 175 176 For(i, 1, word.size() - 1) { 177 key = word[i] - '0'; 178 179 if(p->nxt[!key] != NULL) { 180 ret |= mask; 181 key = !key; 182 } 183 mask >>= 1; 184 p = p->nxt[key]; 185 } 186 return ret; 187 } 188 }; 189 190 int N, ans, arr[maxN]; 191 192 void findMaximumXOR() { 193 Trie trie = Trie(); 194 vector< string > bits; 195 196 Rep(i, N + 1) { 197 bits.push_back(bitset< 32 >(arr[i]).to_string()); 198 trie.insert(bits.back()); 199 ans = max(ans, trie.solve(bits[i])); 200 } 201 } 202 203 int main() { 204 //freopen("MyOutput.txt","w",stdout); 205 //freopen("input.txt","r",stdin); 206 //INIT(); 207 scanf("%d", &N); 208 ans = -inf; 209 For(i, 1, N) { 210 scanf("%d", &arr[i]); 211 arr[i] ^= arr[i - 1]; // 计算前缀异或和 212 } 213 214 if(N == 1) ans = arr[1]; 215 else findMaximumXOR(); // 问题转化为从一个数组中选两个数,使得这两个数的异或和最大 216 217 printf("%d", ans); 218 return 0; 219 } 220 221 /* 222 4 223 -2 -3 -5 -1 224 7 225 1 226 -5 227 -5 228 */