UVA 297 Quadtrees

题目链接:https://vjudge.net/problem/UVA-297

题意摘自《算法禁赛入门经典》

题目大意

  略。

分析

  先递归建树,然后 dfs 求答案。

代码如下

  1 #include <bits/stdc++.h>
  2 using namespace std;
  3  
  4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
  5 #define Rep(i,n) for (int i = 0; i < (int)(n); ++i)
  6 #define For(i,s,t) for (int i = (int)(s); i <= (int)(t); ++i)
  7 #define rFor(i,t,s) for (int i = (int)(t); i >= (int)(s); --i)
  8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i)
  9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i)
 10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i)
 11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i)
 12  
 13 #define pr(x) cout << #x << " = " << x << "  "
 14 #define prln(x) cout << #x << " = " << x << endl
 15  
 16 #define LOWBIT(x) ((x)&(-x))
 17  
 18 #define ALL(x) x.begin(),x.end()
 19 #define INS(x) inserter(x,x.begin())
 20 #define UNIQUE(x) x.erase(unique(x.begin(), x.end()), x.end())
 21 #define REMOVE(x, c) x.erase(remove(x.begin(), x.end(), c), x.end()); // 删去 x 中所有 c 
 22 #define TOLOWER(x) transform(x.begin(), x.end(), x.begin(),::tolower);
 23 #define TOUPPER(x) transform(x.begin(), x.end(), x.begin(),::toupper);
 24  
 25 #define ms0(a) memset(a,0,sizeof(a))
 26 #define msI(a) memset(a,0x3f,sizeof(a))
 27 #define msM(a) memset(a,-1,sizeof(a))
 28 
 29 #define MP make_pair
 30 #define PB push_back
 31 #define ft first
 32 #define sd second
 33  
 34 template<typename T1, typename T2>
 35 istream &operator>>(istream &in, pair<T1, T2> &p) {
 36     in >> p.first >> p.second;
 37     return in;
 38 }
 39  
 40 template<typename T>
 41 istream &operator>>(istream &in, vector<T> &v) {
 42     for (auto &x: v)
 43         in >> x;
 44     return in;
 45 }
 46 
 47 template<typename T>
 48 ostream &operator<<(ostream &out, vector<T> &v) {
 49     Rep(i, v.size()) out << v[i] << " \n"[i == v.size() - 1];
 50     return out;
 51 }
 52  
 53 template<typename T1, typename T2>
 54 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) {
 55     out << "[" << p.first << ", " << p.second << "]" << "\n";
 56     return out;
 57 }
 58 
 59 inline int gc(){
 60     static const int BUF = 1e7;
 61     static char buf[BUF], *bg = buf + BUF, *ed = bg;
 62     
 63     if(bg == ed) fread(bg = buf, 1, BUF, stdin);
 64     return *bg++;
 65 } 
 66 
 67 inline int ri(){
 68     int x = 0, f = 1, c = gc();
 69     for(; c<48||c>57; f = c=='-'?-1:f, c=gc());
 70     for(; c>47&&c<58; x = x*10 + c - 48, c=gc());
 71     return x*f;
 72 }
 73 
 74 template<class T>
 75 inline string toString(T x) {
 76     ostringstream sout;
 77     sout << x;
 78     return sout.str();
 79 }
 80 
 81 inline int toInt(string s) {
 82     int v;
 83     istringstream sin(s);
 84     sin >> v;
 85     return v;
 86 }
 87 
 88 //min <= aim <= max
 89 template<typename T>
 90 inline bool BETWEEN(const T aim, const T min, const T max) {
 91     return min <= aim && aim <= max;
 92 }
 93 
 94 typedef unsigned int uI;
 95 typedef long long LL;
 96 typedef unsigned long long uLL;
 97 typedef vector< int > VI;
 98 typedef vector< bool > VB;
 99 typedef vector< char > VC;
100 typedef vector< double > VD;
101 typedef vector< string > VS;
102 typedef vector< LL > VL;
103 typedef vector< VI > VVI;
104 typedef vector< VB > VVB;
105 typedef vector< VS > VVS;
106 typedef vector< VL > VVL;
107 typedef vector< VVI > VVVI;
108 typedef vector< VVL > VVVL;
109 typedef pair< int, int > PII;
110 typedef pair< LL, LL > PLL;
111 typedef pair< int, string > PIS;
112 typedef pair< string, int > PSI;
113 typedef pair< string, string > PSS;
114 typedef pair< double, double > PDD;
115 typedef vector< PII > VPII;
116 typedef vector< PLL > VPLL;
117 typedef vector< VPII > VVPII;
118 typedef vector< VPLL > VVPLL;
119 typedef vector< VS > VVS;
120 typedef map< int, int > MII;
121 typedef unordered_map< int, int > uMII;
122 typedef map< LL, LL > MLL;
123 typedef map< string, int > MSI;
124 typedef map< int, string > MIS;
125 typedef multiset< int > mSI;
126 typedef set< int > SI;
127 typedef stack< int > SKI;
128 typedef deque< int > DQI;
129 typedef queue< int > QI;
130 typedef priority_queue< int > PQIMax;
131 typedef priority_queue< int, VI, greater< int > > PQIMin;
132 const double EPS = 1e-8;
133 const LL inf = 0x7fffffff;
134 const LL infLL = 0x7fffffffffffffffLL;
135 const LL mod = 1e9 + 7;
136 const int maxN = 1e4 + 7;
137 const LL ONE = 1;
138 const LL evenBits = 0xaaaaaaaaaaaaaaaa;
139 const LL oddBits = 0x5555555555555555;
140 
141 struct QuadtreeNode {
142     char type;
143     int num;
144     QuadtreeNode* nxt[4];
145     
146     QuadtreeNode(char tp) : type(tp) {
147         Rep(i, 4) nxt[i] = nullptr;
148     }
149 };
150 
151 int N;
152 string str1, str2;
153 QuadtreeNode* root1 = nullptr;
154 QuadtreeNode* root2 = nullptr;
155 
156 int build(QuadtreeNode* &rt, string &str, int p, int cnt) { // 要传指针的引用,不然建树的时候指针就不是树上的指针了 
157     assert(p < str.size() && rt == nullptr);
158     rt = new QuadtreeNode(str[p]);
159     
160     switch(str[p]) {
161         case 'p':{
162             ++p;
163             rt->num = 0;
164             Rep(i, 4) {
165                 p = build(rt->nxt[i], str, p, cnt >> 2);
166                 rt->num += rt->nxt[i]->num;
167             }
168             return p;
169         }
170         case 'f':{
171             rt->num = cnt;
172             return p + 1;
173         }
174         case 'e':{
175             rt->num = 0;
176             return p + 1;
177         }
178         default:{
179             assert(false);
180         }
181     }
182 }
183 
184 void clear(QuadtreeNode* &rt) {
185     if(rt == nullptr) return;
186     Rep(i, 4) {
187         if(rt->nxt[i] != nullptr) {
188             clear(rt->nxt[i]);
189         }
190     }
191     delete rt;
192     rt = nullptr;
193 }
194 
195 int solve(QuadtreeNode* &rt1, QuadtreeNode* &rt2) {
196     int ret = 0;
197     
198     if(rt1->type == 'p' && rt2->type == 'p') {
199         Rep(i, 4) ret += solve(rt1->nxt[i], rt2->nxt[i]);
200     }
201     else ret = max(rt1->num, rt2->num);
202     
203     return ret;
204 }
205 
206 int main() {
207     //freopen("MyOutput.txt","w",stdout);
208     //freopen("input.txt","r",stdin);
209     //INIT();
210     cin >> N;
211     while(N--) {
212         clear(root1);
213         clear(root2);
214         cin >> str1 >> str2;
215         
216         build(root1, str1, 0, 1024);
217         build(root2, str2, 0, 1024);
218         
219         printf("There are %d black pixels.\n", solve(root1, root2));
220     }
221     return 0;
222 }
View Code

 

posted @ 2019-08-21 17:50  梦樱羽  阅读(154)  评论(0编辑  收藏  举报
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