牛客 可见山峰对数量（进阶）
题目大意
略。
分析
由于有重复值，每个点的贡献就不确定了，我们需要借助单调栈，因为单调栈能找到离当前山峰最近大的山峰。
具体见左神的书。
代码如下
1 #include <bits/stdc++.h> 2 using namespace std; 3 4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0); 5 #define Rep(i,n) for (int i = 0; i < (int)(n); ++i) 6 #define For(i,s,t) for (int i = (int)(s); i <= (int)(t); ++i) 7 #define rFor(i,t,s) for (int i = (int)(t); i >= (int)(s); --i) 8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i) 9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i) 10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i) 11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i) 12 13 #define pr(x) cout << #x << " = " << x << " " 14 #define prln(x) cout << #x << " = " << x << endl 15 16 #define LOWBIT(x) ((x)&(-x)) 17 18 #define ALL(x) x.begin(),x.end() 19 #define INS(x) inserter(x,x.begin()) 20 #define UNIQUE(x) x.erase(unique(x.begin(), x.end()), x.end()) 21 #define REMOVE(x, c) x.erase(remove(x.begin(), x.end(), c), x.end()); // 删去 x 中所有 c 22 #define TOLOWER(x) transform(x.begin(), x.end(), x.begin(),::tolower); 23 #define TOUPPER(x) transform(x.begin(), x.end(), x.begin(),::toupper); 24 25 #define ms0(a) memset(a,0,sizeof(a)) 26 #define msI(a) memset(a,0x3f,sizeof(a)) 27 #define msM(a) memset(a,-1,sizeof(a)) 28 29 #define MP make_pair 30 #define PB push_back 31 #define ft first 32 #define sd second 33 34 template<typename T1, typename T2> 35 istream &operator>>(istream &in, pair<T1, T2> &p) { 36 in >> p.first >> p.second; 37 return in; 38 } 39 40 template<typename T> 41 istream &operator>>(istream &in, vector<T> &v) { 42 for (auto &x: v) 43 in >> x; 44 return in; 45 } 46 47 template<typename T> 48 ostream &operator<<(ostream &out, vector<T> &v) { 49 Rep(i, v.size()) out << v[i] << " \n"[i == v.size()]; 50 return out; 51 } 52 53 template<typename T1, typename T2> 54 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) { 55 out << "[" << p.first << ", " << p.second << "]" << "\n"; 56 return out; 57 } 58 59 inline int gc(){ 60 static const int BUF = 1e7; 61 static char buf[BUF], *bg = buf + BUF, *ed = bg; 62 63 if(bg == ed) fread(bg = buf, 1, BUF, stdin); 64 return *bg++; 65 } 66 67 inline int ri(){ 68 int x = 0, f = 1, c = gc(); 69 for(; c<48||c>57; f = c=='-'?-1:f, c=gc()); 70 for(; c>47&&c<58; x = x*10 + c - 48, c=gc()); 71 return x*f; 72 } 73 74 template<class T> 75 inline string toString(T x) { 76 ostringstream sout; 77 sout << x; 78 return sout.str(); 79 } 80 81 inline int toInt(string s) { 82 int v; 83 istringstream sin(s); 84 sin >> v; 85 return v; 86 } 87 88 //min <= aim <= max 89 template<typename T> 90 inline bool BETWEEN(const T aim, const T min, const T max) { 91 return min <= aim && aim <= max; 92 } 93 94 typedef long long LL; 95 typedef unsigned long long uLL; 96 typedef vector< int > VI; 97 typedef vector< bool > VB; 98 typedef vector< char > VC; 99 typedef vector< double > VD; 100 typedef vector< string > VS; 101 typedef vector< LL > VL; 102 typedef vector< VI > VVI; 103 typedef vector< VB > VVB; 104 typedef vector< VS > VVS; 105 typedef vector< VL > VVL; 106 typedef vector< VVI > VVVI; 107 typedef vector< VVL > VVVL; 108 typedef pair< int, int > PII; 109 typedef pair< LL, LL > PLL; 110 typedef pair< int, string > PIS; 111 typedef pair< string, int > PSI; 112 typedef pair< string, string > PSS; 113 typedef pair< double, double > PDD; 114 typedef vector< PII > VPII; 115 typedef vector< PLL > VPLL; 116 typedef vector< VPII > VVPII; 117 typedef vector< VPLL > VVPLL; 118 typedef vector< VS > VVS; 119 typedef map< int, int > MII; 120 typedef unordered_map< int, int > uMII; 121 typedef map< LL, LL > MLL; 122 typedef map< string, int > MSI; 123 typedef map< int, string > MIS; 124 typedef set< int > SI; 125 typedef stack< int > SKI; 126 typedef deque< int > DQI; 127 typedef queue< int > QI; 128 typedef priority_queue< int > PQIMax; 129 typedef priority_queue< int, VI, greater< int > > PQIMin; 130 const double EPS = 1e-8; 131 const LL inf = 0x7fffffff; 132 const LL infLL = 0x7fffffffffffffffLL; 133 const LL mod = 1e9 + 7; 134 const int maxN = 1e6 + 7; 135 const LL ONE = 1; 136 const LL evenBits = 0xaaaaaaaaaaaaaaaa; 137 const LL oddBits = 0x5555555555555555; 138 139 struct Record { 140 int value, times; 141 142 Record(int v) { 143 value = v; 144 times = 1; 145 } 146 }; 147 148 int N, arr[maxN]; 149 int maxH = -inf, S; // 最高山峰（不止一座）的高度及其位置 150 stack< Record > sk; // 单调栈 151 LL ans; 152 153 int main(){ 154 //freopen("MyOutput.txt","w",stdout); 155 //freopen("input.txt","r",stdin); 156 //INIT(); 157 scanf("%d", &N); 158 Rep(i, N) { 159 scanf("%d", &arr[i]); 160 if(maxH < arr[i]) { 161 maxH = arr[i]; 162 S = i; 163 } 164 } 165 sk.push(Record(arr[S])); // 以最大值作为左边界 166 167 For(i, 1, N - 1) { 168 int id = (S + i) % N; 169 170 while(sk.top().value < arr[id]) { 171 int tmp = sk.top().times; sk.pop(); 172 173 ans += (tmp - 1) * tmp / 2 + 2 * tmp; 174 } 175 if(sk.top().value == arr[id]) ++sk.top().times; 176 else sk.push(Record(arr[id])); 177 } 178 while(!sk.empty()) { 179 int tmp = sk.top().times; sk.pop(); 180 181 ans += (tmp - 1) * tmp / 2; // 内部产生山峰对 182 183 if(sk.size() == 1 && sk.top().times == 1) ans += tmp; 184 else if(sk.size() != 0) ans += 2 * tmp; 185 } 186 187 printf("%d\n", ans); 188 return 0; 189 }
