NSDictionary 的有序性 (by the key in some rule)

NSDictionary 的有序性: (by the key in some rule)

NSDictionary*myDictionary =[NSDictionary dictionaryWithObjectsAndKeys:@"o1",@"k1",@"o6",@"k4",@"o2",@"k2",@"o3",@"k3",@"o5",@"k5", nil];NSInteger count =[myDictionary count];

如下代码1:

  NSLog(@"%@ ", [myDictionary allKeys]);

    NSLog(@"%@ ", [myDictionary allValues]);

    

每次运行都是这样的结果

2014-04-10 10:55:58.548[3105:70b] (

    k4,

    k3,

    k2,

    k5,

    k1

2014-04-10 10:55:58.548[3105:70b] (

    o6,

    o3,

    o2,

    o5,

    o1

)

修改k4 --> k6 

每次运行结果为

2014-04-10 10:53:38.318[3083:70b] (

    k3,

    k6,

    k2,

    k5,

    k1

2014-04-10 10:53:38.318[3083:70b] (

    o3,

    o6,

    o2,

    o5,

    o1

 

    

 

如下代码2:

    id __unsafe_unretained objects[count];

    id  __unsafe_unretained keys[count];

    [myDictionary getObjects:objects andKeys:keys];

    

    for(int i =0; i < count; i++){

        id obj = objects[i];

        id key = keys[i];NSLog(@"%@ -> %@", obj, key);

    }

每次运行都是这样的结果

o6 -> k4

o3 -> k3

o2 -> k2

o5 -> k5

o1 -> k1

修改k4 --> k6 

每次运行结果为

o3 -> k3

o6 -> k6

o2 -> k2

o5 -> k5

o1 -> k1

由此可知

NSDictionary  其实是有序的: (by the key in some rule) 根据key进行排序

posted @ 2014-04-10 10:34  zander  阅读(1870)  评论(0编辑  收藏  举报