HDU1209--Clock

Clock
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 3468 Accepted Submission(s): 1069


Problem Description
There is an analog clock with two hands: an hour hand and a minute hand. The two hands form an angle. The angle is measured as the smallest angle between the two hands. The angle between the two hands has a measure that is greater than or equal to 0 and less than or equal to 180 degrees.

Given a sequence of five distinct times written in the format hh : mm , where hh are two digits representing full hours (00 <= hh <= 23) and mm are two digits representing minutes (00 <= mm <= 59) , you are to write a program that finds the median, that is, the third element of the sorted sequence of times in a nondecreasing order of their associated angles. Ties are broken in such a way that an earlier time precedes a later time.

For example, suppose you are given a sequence (06:05, 07:10, 03:00, 21:00, 12:55) of times. Because the sorted sequence is (12:55, 03:00, 21:00, 06:05, 07:10), you are to report 21:00.


Input
The input consists of T test cases. The number of test cases (T) is given on the first line of the input file. Each test case is given on a single line, which contains a sequence of five distinct times, where times are given in the format hh : mm and are separated by a single space.


Output
Print exactly one line for each test case. The line is to contain the median in the format hh : mm of the times given. The following shows sample input and output for three test cases.


Sample Input
3
00:00 01:00 02:00 03:00 04:00
06:05 07:10 03:00 21:00 12:55
11:05 12:05 13:05 14:05 15:05


Sample Output
02:00
21:00
14:05


Source
Asia 2003（Seoul）


Recommend
mcqsmall

 

 

#include<cstdio>
#include<cmath>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;

struct Node
{
    int hour,minute;
    double angle;
    int time;
}fnode[5];

bool cmp(Node a,Node b)
{
    if(fabs(a.angle-b.angle)<1e-6)
    {
        return a.time<b.time;
    }
    return a.angle<b.angle;
}

int n;

int main()
{
    scanf("%d",&n);
    while(n--)
    {
        int i;
        for(i=0;i<5;i++)
        {
            int hour,minute;
            scanf("%d:%d",&fnode[i].hour,&fnode[i].minute);
            fnode[i].time=fnode[i].hour*60+fnode[i].minute;
            hour=fnode[i].hour,minute=fnode[i].minute;
            if(fnode[i].hour>=12)hour-=12;
            fnode[i].angle=fabs(hour*1.0/12*360-minute*1.0/60*360+minute/2.0);
            if(fnode[i].angle>=180)
            {
                fnode[i].angle=360-fnode[i].angle;
            }
        }
        sort(fnode,fnode+5,cmp);
        if(fnode[2].hour<10)
        {
            printf("0%d:",fnode[2].hour);
        }
        else
            printf("%d:",fnode[2].hour);
        if(fnode[2].minute<10)
        {
            printf("0%d\n",fnode[2].minute);
        }
        else
            printf("%d\n",fnode[2].minute);
    }
    return 0;
}