java/groovy 计算时间

Java

String dateStart = "01/14/2015 08:29:58";
String dateStop = "01/15/2015 11:31:48";

//HH converts hour in 24 hours format (0-23), day calculation
SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");

Date d1 = null;
Date d2 = null;

d1 = format.parse(dateStart);
d2 = format.parse(dateStop);

//in milliseconds
long diff = d2.getTime() - d1.getTime();

long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffDays = diff / (24 * 60 * 60 * 1000);

System.out.print(diffDays + " days, ");
System.out.print(diffHours + " hours, ");
System.out.print(diffMinutes + " minutes, ");
System.out.print(diffSeconds + " seconds.");

 

Groovy

import java.text.SimpleDateFormat;
def dateStart = "01/14/2015 08:29:58";
def dateStop = "01/15/2015 11:31:48";

SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");

Date d1=format.parse(dateStart)
Date d2=format.parse(dateStop)

log.info(d1.getTime())

long diffMilliseconds = d2.getTime() - d1.getTime()
long diffSecondsTemp = diffMilliseconds / 1000
long diffSeconds = diffSecondsTemp % 60
log.info(diffSeconds)

long diffMinutesTemp = diffMilliseconds / (60 * 1000)
long diffMinutes = diffMinutesTemp % 60
log.info(diffMinutes)

long diffHoursTemp = diffMilliseconds / (60 * 60 * 1000)
long diffHours = diffHoursTemp % 24
log.info(diffHours)

long diffDays = diffMilliseconds / (24 * 60 * 60 * 1000)
log.info(diffDays)

  

posted @ 2016-11-10 14:04  lily_z  阅读(6091)  评论(0编辑  收藏  举报