Advent of Code 2015: Day 10
JP's Blog
Advent of Code 2015: Day 10
https://blog.jverkamp.com/2015/12/10/advent-of-code-day-10/
Part 1: Repeat a Look-and-say sequence 40 times. Return the length.
def look_and_say(seq):
result = ''
index = 0
count = 0
buffer = None
for c in seq:
if c == buffer:
count += 1
else:
if buffer:
result += '{}{}'.format(count, buffer)
count = 1
buffer = c
result += '{}{}'.format(count, buffer)
return result
def repeat(f, n, seq):
for i in range(n):
seq = f(seq)
return seq
print(len(repeat(look_and_say, int(sys.argv[2]), sys.argv[1])))
I’ve already gone into far more detail on Look and Say sequences before. But this time, we’re doing it iteratively in Python! Basically, we just maintain a bit of state for which character we are currently counting. When we change, output; otherwise, incrememnt the change.
There are some interesting tricks you could do with regular expressions, but I doubt you can find something faster or much more elegant than this.
Part 2: Repeat 50 times.
There’s nothing particular interesting about this one. I’ve already accounted for this by passing in the second paramter on the command line.
自然语言处理爱好者,欢迎交流。QQ: 7214218
分类:
Python
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】抖音旗下AI助手豆包,你的智能百科全书,全免费不限次数
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步
· 被坑几百块钱后,我竟然真的恢复了删除的微信聊天记录!
· 没有Manus邀请码?试试免邀请码的MGX或者开源的OpenManus吧
· 【自荐】一款简洁、开源的在线白板工具 Drawnix
· 园子的第一款AI主题卫衣上架——"HELLO! HOW CAN I ASSIST YOU TODAY
· Docker 太简单,K8s 太复杂?w7panel 让容器管理更轻松!