Educational Round 26 A. Text Volume

A. Text Volume

You are given a text of single-space separated words, consisting of small and capital Latin letters.

Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the text.

Calculate the volume of the given text.

Input

The first line contains one integer number n (1 ≤ n ≤ 200) — length of the text.

The second line contains text of single-space separated words s₁, s₂, ..., s_i, consisting only of small and capital Latin letters.

Output

Print one integer number — volume of text.

Examples

Input

7
NonZERO

Output

5

Input

24
this is zero answer text

Output

0

Input

24
Harbour Space University

Output

1

Note

In the first example there is only one word, there are 5 capital letters in it.

In the second example all of the words contain 0 capital letters.

 

/*
scanf输入字符串,整型,实型等数据判断的方式都一样
回车,空格,tab键都认为是一个数据的结束,当然字符的话
一个字符就是结束了,回车,空格等都有对应的ascii码
所以用scanf输入字符时要小心这些东东被当成字符输进去
而输入字符串和整型,实型等数据时这些都被当成分隔符而不会被输入到字符数组或变量里。
for(int i=0;i<10;++i){
    char ch=getchar();
    fflush(stdin); //每次都会有等待状态了（VC平台）
    printf ( "ch=%c\n", ch );
}
*/
#include <iostream>
#include <stdio.h>

using namespace std;
int mx=0,t=0;
char c;
int main(){
    int n;
    //ios::sync_with_stdio(false);
        scanf("%d",&n);
        for(int i=0;i<=n;i++){
        c=getchar();
         if(c==' '){
            mx=max(mx,t);
            t=0;
         }else {
             if (c<='Z'&&c>='A') {
                t++;
              }
            }
        }
           mx=max(mx,t);
    printf("%d\n",mx);
    return 0;
}