explicit运算符
引用StackOverFlow中的例子:
struct Foo {
int value; // Foo stores an int, called value
Foo(int v):value(v) {}; // Foo can be constructed (created) from an int
explicit Foo(double d):value(d) {}; // Foo can be constructed (created) from a double
// ^^^ note that keyword. It says that it can only be EXPLICITLY created from a double
};
按照规定,只有一个参数的构造函数也定义了一个隐式转换,将该构造函数对应数据类型的数据转换为该类对象
在此构造函数前加了explicit后,用来抑制隐式转换
explicit只对构造函数起作用
Foo i = 0.0;
This fails to compile. I said that the constructor for Foo(double)
is explicit, and the above only chooses to call constructors that are non-explicit. On the other hand:
Foo i(0.0);
Foo i = Foo(0.0);
these both are willing to call explicit constructors, and work fine.
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