VUE 分组取最大，生成子集合

// 分组函数  

const groupByAge = (docs: TOSDepositoryDTO[]): Record<number, TOSDepositoryDTO[]> => {

  return docs.reduce((acc, d) => {

    if (!acc[d.approvalId]) acc[d.approvalId] = [];

    acc[d.approvalId].push(d);

    return acc;

  }, {} as Record<number, TOSDepositoryDTO[]>);

};

// 获取每组最大用户和其他用户的函数  

const getMaxUserWithOthersByAge = (docs: TOSDepositoryDTO[]) => {

  const groupedUsers = groupByAge(docs);

  return Object.entries(groupedUsers).map(([approvalId, usersGroup]) => {

    // 根据 id 获取最大用户  

    const maxUser = usersGroup.reduce((max, current) => (current.revisionNumber > max.revisionNumber ? current : max));

    maxUser.items = usersGroup.filter(user => user.id !== maxUser.id); // 过滤掉最大用户，生成其他用户的子数组  

    return maxUser;

  });

};

const getTOSDepository = async () => {

  var resDoc = await ClientService.getTOSDepository(model.value.id);

  documents.value = getMaxUserWithOthersByAge(resDoc);

  console.log(documents.value);

}

 

 

 

 

const sectorList = ref<SectorDTO[]>();

const industrySectorList = ref<SectorDTO[]>();

  sectorList.value = industrySectorList.value?.filter(m => selectIndustrys.value?.includes(m.industryID))

 

 

 

watch([selectIndustrys], () => {

  console.log(3311111, selectIndustrys.value);

  sectorList.value = industrySectorList.value?.filter(m => selectIndustrys.value?.includes(m.industryID))

  // if (selectIndustrys.value)

  //   IndustryList.value?.filter(m => selectIndustrys.value?.includes(m.industryID)).forEach(i => { console.log(111, i.items); sectorList.value?.concat(i.items) })

})

  IndustryList.value = industrySectorList.value.reduce<SectorDTO[]>((accumulator, current) => {

    const exists = accumulator.some(item => item.industryName === current.industryName && item.industryID === current.industryID);

    if (!exists)   accumulator.push(current); console.log(5555, current);

     return accumulator;

  }, []);