python实验3task2

def fun(n):
    if n <=1:
        return n
    else:return fun(n-1)+fun(n-2)
for n in range(17):
    print(fun(n))
m=1
for n in [fun(n)]:
    print(f'{n:4d}',end=' 'if m%5 else '/n')
    m+=1

posted @ 2021-04-23 13:07  yyyl  阅读(44)  评论(1编辑  收藏  举报