实验任务1:
实验代码:
button.hpp:
1 #pragma once 2 3 #include <iostream> 4 #include <string> 5 6 using std::string; 7 using std::cout; 8 9 // 按钮类 10 class Button { 11 public: 12 Button(const string &text); 13 string get_label() const; 14 void click(); 15 16 private: 17 string label; 18 }; 19 20 Button::Button(const string &text): label{text} { 21 } 22 23 inline string Button::get_label() const { 24 return label; 25 } 26 27 void Button::click() { 28 cout << "Button '" << label << "' clicked\n"; 29 }
window.hpp:
1 #pragma once 2 #include "button.hpp" 3 #include <vector> 4 #include <iostream> 5 6 using std::vector; 7 using std::cout; 8 using std::endl; 9 10 // 窗口类 11 class Window{ 12 public: 13 Window(const string &win_title); 14 void display() const; 15 void close(); 16 void add_button(const string &label); 17 18 private: 19 string title; 20 vector<Button> buttons; 21 }; 22 23 Window::Window(const string &win_title): title{win_title} { 24 buttons.push_back(Button("close")); 25 } 26 27 inline void Window::display() const { 28 string s(40, '*'); 29 30 cout << s << endl; 31 cout << "window title: " << title << endl; 32 cout << "It has " << buttons.size() << " buttons: " << endl; 33 for(const auto &i: buttons) 34 cout << i.get_label() << " button" << endl; 35 cout << s << endl; 36 } 37 38 void Window::close() { 39 cout << "close window '" << title << "'" << endl; 40 buttons.at(0).click(); 41 } 42 43 void Window::add_button(const string &label) { 44 buttons.push_back(Button(label)); 45 }
task1.cpp:
1 #include "window.hpp" 2 #include <iostream> 3 4 using std::cout; 5 using std::cin; 6 7 void test() { 8 Window w1("new window"); 9 w1.add_button("maximize"); 10 w1.display(); 11 w1.close(); 12 } 13 14 int main() { 15 cout << "用组合类模拟简单GUI:\n"; 16 test(); 17 }
实验截图:
问题1:自定义了两个类,Button和Window;使用了标准库中两个类,string和vector;Button与string有组合关系,Window与string、Button、vector有组合关系。
问题2:Button类中的函数void click()适合设置成inline,该函数较小且简单,并且在实际应用中可能被多次调用。
问题3:生成一个string类对象s,其长度为40,且其中每个字符都为‘*’。
实验任务2:
实验代码:
task2.cpp:
1 #include <iostream> 2 #include <vector> 3 4 using namespace std; 5 6 void output1(const vector<int> &v) { 7 for(auto &i: v) 8 cout << i << ", "; 9 cout << "\b\b \n"; 10 } 11 12 void output2(const vector<vector<int>> v) { 13 for(auto &i: v) { 14 for(auto &j: i) 15 cout << j << ", "; 16 cout << "\b\b \n"; 17 } 18 } 19 20 void test1() { 21 vector<int> v1(5, 42); 22 const vector<int> v2(v1); 23 24 v1.at(0) = -999; 25 cout << "v1: "; output1(v1); 26 cout << "v2: "; output1(v2); 27 cout << "v1.at(0) = " << v1.at(0) << endl; 28 cout << "v2.at(0) = " << v2.at(0) << endl; 29 } 30 31 void test2() { 32 vector<vector<int>> v1{{1, 2, 3}, {4, 5, 6, 7}}; 33 const vector<vector<int>> v2(v1); 34 35 v1.at(0).push_back(-999); 36 cout << "v1: \n"; output2(v1); 37 cout << "v2: \n"; output2(v2); 38 39 vector<int> t1 = v1.at(0); 40 cout << t1.at(t1.size()-1) << endl; 41 42 const vector<int> t2 = v2.at(0); 43 cout << t2.at(t2.size()-1) << endl; 44 } 45 46 int main() { 47 cout << "测试1:\n"; 48 test1(); 49 50 cout << "\n测试2:\n"; 51 test2(); 52 }
实验截图:
问题1:第一行:定义一个int类型的vector数组v1,其长度为5,其中每个数据都为42。
第二行:定义一个int类型的vector数组v2,用v1的值来初始化。
第三行:将v1数组的第一个成员赋值为-999。
问题2:第一行:定义了一个int类型的名为v1的二维vector数组,第一个元素为vector数组{1,2,3},第二个元素为vector数组{4,5,6,7}。
第二行:定义了一个int类型的名为v2的二维常量vector数组,用v1的值来初始化。
第三行:在二维vector数组v1第一个元素vector数组的末尾添加一个新元素-999。
问题3:第一行:定义一个int类型的vector数组t1,并用二维vector数组v1的第一个元素来初始化。
第二行:输出t1的最后一个元素的值。
第三行:定义了一个int类型的名为t2的常量vector数组,用v2的第一个元素来初始化。
第四行:输出t2的最后一个元素的值。
问题4:深复制;不需要。
实验任务3:
实验代码:
vectorInt.hpp:
1 #pragma once 2 3 #include <iostream> 4 #include <cassert> 5 6 using std::cout; 7 using std::endl; 8 9 // 动态int数组对象类 10 class vectorInt{ 11 public: 12 vectorInt(int n); 13 vectorInt(int n, int value); 14 vectorInt(const vectorInt &vi); 15 ~vectorInt(); 16 17 int& at(int index); 18 const int& at(int index) const; 19 20 vectorInt& assign(const vectorInt &v); 21 int get_size() const; 22 23 private: 24 int size; 25 int *ptr; // ptr指向包含size个int的数组 26 }; 27 28 vectorInt::vectorInt(int n): size{n}, ptr{new int[size]} { 29 } 30 31 vectorInt::vectorInt(int n, int value): size{n}, ptr{new int[size]} { 32 for(auto i = 0; i < size; ++i) 33 ptr[i] = value; 34 } 35 36 vectorInt::vectorInt(const vectorInt &vi): size{vi.size}, ptr{new int[size]} { 37 for(auto i = 0; i < size; ++i) 38 ptr[i] = vi.ptr[i]; 39 } 40 41 vectorInt::~vectorInt() { 42 delete [] ptr; 43 } 44 45 const int& vectorInt::at(int index) const { 46 assert(index >= 0 && index < size); 47 48 return ptr[index]; 49 } 50 51 int& vectorInt::at(int index) { 52 assert(index >= 0 && index < size); 53 54 return ptr[index]; 55 } 56 57 vectorInt& vectorInt::assign(const vectorInt &v) { 58 delete[] ptr; // 释放对象中ptr原来指向的资源 59 60 size = v.size; 61 ptr = new int[size]; 62 63 for(int i = 0; i < size; ++i) 64 ptr[i] = v.ptr[i]; 65 66 return *this; 67 } 68 69 int vectorInt::get_size() const { 70 return size; 71 }
task3.cpp:
1 #include "vectorInt.hpp" 2 #include <iostream> 3 4 using std::cin; 5 using std::cout; 6 7 void output(const vectorInt &vi) { 8 for(auto i = 0; i < vi.get_size(); ++i) 9 cout << vi.at(i) << ", "; 10 cout << "\b\b \n"; 11 } 12 13 14 void test1() { 15 int n; 16 cout << "Enter n: "; 17 cin >> n; 18 19 vectorInt x1(n); 20 for(auto i = 0; i < n; ++i) 21 x1.at(i) = i*i; 22 cout << "x1: "; output(x1); 23 24 vectorInt x2(n, 42); 25 vectorInt x3(x2); 26 x2.at(0) = -999; 27 cout << "x2: "; output(x2); 28 cout << "x3: "; output(x3); 29 } 30 31 void test2() { 32 const vectorInt x(5, 42); 33 vectorInt y(10, 0); 34 35 cout << "y: "; output(y); 36 y.assign(x); 37 cout << "y: "; output(y); 38 39 cout << "x.at(0) = " << x.at(0) << endl; 40 cout << "y.at(0) = " << y.at(0) << endl; 41 } 42 43 int main() { 44 cout << "测试1: \n"; 45 test1(); 46 47 cout << "\n测试2: \n"; 48 test2(); 49 }
实验截图:
问题1:深复制。
问题2:可以正确运行。有安全隐患,const有助于保证数据不被意外修改。
问题3:可以改成。返回对象改成vectorInt后每次调用assign()函数会创建一个新的vectorInt对象,性能会降低但不影响实现。
实验任务4:
实验代码:
matrix.hpp:
1 #pragma once 2 3 #include <iostream> 4 #include <cassert> 5 6 using std::cout; 7 using std::endl; 8 9 // 类Matrix的声明 10 class Matrix { 11 public: 12 Matrix(int n, int m); // 构造函数,构造一个n*m的矩阵, 初始值为value 13 Matrix(int n); // 构造函数,构造一个n*n的矩阵, 初始值为value 14 Matrix(const Matrix &x); // 复制构造函数, 使用已有的矩阵X构造 15 ~Matrix(); 16 17 void set(const double *pvalue); // 用pvalue指向的连续内存块数据按行为矩阵赋值 18 void clear(); // 把矩阵对象的值置0 19 20 const double& at(int i, int j) const; // 返回矩阵对象索引(i,j)的元素const引用 21 double& at(int i, int j); // 返回矩阵对象索引(i,j)的元素引用 22 23 int get_lines() const; // 返回矩阵对象行数 24 int get_cols() const; // 返回矩阵对象列数 25 26 void display() const; // 按行显示矩阵对象元素值 27 28 private: 29 int lines; // 矩阵对象内元素行数 30 int cols; // 矩阵对象内元素列数 31 double *ptr; 32 }; 33 34 // 类Matrix的实现:待补足 35 Matrix::Matrix(int n, int m): lines{n}, cols{m} { 36 ptr = new double[n*m]; 37 } 38 39 Matrix::Matrix(int n): lines{n}, cols{n} { 40 ptr = new double[n*n]; 41 } 42 43 Matrix::Matrix(const Matrix &x): lines{x.lines}, cols{x.cols} { 44 ptr = new double[lines*cols]; 45 for(int i = 0; i < lines*cols; i++) ptr[i] = x.ptr[i]; 46 } 47 48 void Matrix::set(const double *pvalue) { 49 for(int i = 0; i < lines*cols; i++) 50 ptr[i] = pvalue[i]; 51 } 52 53 void Matrix::clear() { 54 for(int i = 0; i < lines*cols; i++) 55 ptr[i] = 0; 56 } 57 58 const double& Matrix::at(int i, int j) const { 59 assert(i >= 0 && i < lines && j >= 0 && j < cols); 60 return ptr[i*cols + j]; 61 } 62 63 double& Matrix::at(int i, int j) { 64 assert(i >= 0 && i < lines && j >=0 && j < cols); 65 return ptr[i*cols + j]; 66 } 67 68 int Matrix::get_lines() const { 69 return lines; 70 } 71 72 int Matrix::get_cols() const { 73 return cols; 74 } 75 76 void Matrix::display() const { 77 for(int i = 0; i < lines; i++) { 78 for(int j = 0; j < cols; j++) 79 cout << ptr[i*cols + j] << ", "; 80 cout << "\n"; 81 } 82 }
task4.cpp:
1 #include "matrix.hpp" 2 #include <iostream> 3 #include <cassert> 4 5 using std::cin; 6 using std::cout; 7 using std::endl; 8 9 10 const int N = 1000; 11 12 // 输出矩阵对象索引为index所在行的所有元素 13 void output(const Matrix &m, int index) { 14 assert(index >= 0 && index < m.get_lines()); 15 16 for(auto j = 0; j < m.get_cols(); ++j) 17 cout << m.at(index, j) << ", "; 18 cout << "\b\b \n"; 19 } 20 21 22 void test1() { 23 double x[1000] = {1, 2, 3, 4, 5, 6, 7, 8, 9}; 24 25 int n, m; 26 cout << "Enter n and m: "; 27 cin >> n >> m; 28 29 Matrix m1(n, m); // 创建矩阵对象m1, 大小n×m 30 m1.set(x); // 用一维数组x的值按行为矩阵m1赋值 31 32 Matrix m2(m, n); // 创建矩阵对象m1, 大小m×n 33 m2.set(x); // 用一维数组x的值按行为矩阵m1赋值 34 35 Matrix m3(2); // 创建一个2×2矩阵对象 36 m3.set(x); // 用一维数组x的值按行为矩阵m4赋值 37 38 cout << "矩阵对象m1: \n"; m1.display(); cout << endl; 39 cout << "矩阵对象m2: \n"; m2.display(); cout << endl; 40 cout << "矩阵对象m3: \n"; m3.display(); cout << endl; 41 } 42 43 void test2() { 44 Matrix m1(2, 3); 45 m1.clear(); 46 47 const Matrix m2(m1); 48 m1.at(0, 0) = -999; 49 50 cout << "m1.at(0, 0) = " << m1.at(0, 0) << endl; 51 cout << "m2.at(0, 0) = " << m2.at(0, 0) << endl; 52 cout << "矩阵对象m1第0行: "; output(m1, 0); 53 cout << "矩阵对象m2第0行: "; output(m2, 0); 54 } 55 56 int main() { 57 cout << "测试1: \n"; 58 test1(); 59 60 cout << "测试2: \n"; 61 test2(); 62 }
实验截图:
实验任务5:
实验代码:
user.hpp:
1 #pragma once 2 3 #include <iostream> 4 #include <vector> 5 #include <string> 6 7 using namespace std; 8 9 class User { 10 public: 11 User(const string& name0, const string& password0 = "123456", const string& email0 = " "); 12 void set_email(); 13 void change_password(); 14 void display() const; 15 private: 16 string name; 17 string password; 18 string email; 19 }; 20 21 User::User(const string& name0, const string& password0, const string& email0) : name{name0}, password{password0}, email{email0} {} 22 void User::set_email() { 23 string input_email; 24 cout << "Enter email address:"; 25 cin >> input_email; 26 while(true) { 27 if(input_email.find('@') != string::npos) { 28 email = input_email; 29 cout << "email is set successfully..." << endl; 30 break; 31 } 32 else { 33 cout << "illegal email. Please re-enter email:"; 34 cin >> input_email; 35 } 36 } 37 } 38 39 void User::change_password() { 40 cout << "Enter old password:"; 41 string input_password,newpassword; 42 int count = 0; 43 cin >> input_password; 44 while(count < 2) { 45 if(input_password == password) { 46 cout << "Enter new password:"; 47 cin >> newpassword; 48 password = newpassword; 49 cout << "new password is set successfully..." << endl; 50 break; 51 } 52 else { 53 cout << "password input error. Please re-enter again: "; 54 cin >> input_password; 55 count++; 56 } 57 } 58 if(count == 2) { 59 cout << "password input error. Please try after a while." << endl; 60 } 61 } 62 63 void User::display() const { 64 cout << "用户名:" << name << endl; 65 cout << "密码:" << string(password.length(),'*') << endl; 66 cout << "邮箱:" << email << endl; 67 }
task5.cpp:
1 #include "user.hpp" 2 #include <iostream> 3 #include <vector> 4 #include <string> 5 6 using std::cin; 7 using std::cout; 8 using std::endl; 9 using std::vector; 10 using std::string; 11 12 void test() { 13 vector<User> user_lst; 14 15 User u1("Alice", "2024113", "Alice@hotmail.com"); 16 user_lst.push_back(u1); 17 cout << endl; 18 19 User u2("Bob"); 20 u2.set_email(); 21 u2.change_password(); 22 user_lst.push_back(u2); 23 cout << endl; 24 25 User u3("Hellen"); 26 u3.set_email(); 27 u3.change_password(); 28 user_lst.push_back(u3); 29 cout << endl; 30 31 cout << "There are " << user_lst.size() << " users. they are: " << endl; 32 for(auto &i: user_lst) { 33 i.display(); 34 cout << endl; 35 } 36 } 37 38 int main() { 39 test(); 40 }
实验截图:
实验任务6:
实验代码:
date.h:
1 #pragma once 2 class Date { 3 private: 4 int year; 5 int month; 6 int day; 7 int totalDays; 8 public: 9 Date(int year, int month, int day); 10 int getYear() const {return year;} 11 int getMonth() const {return month;} 12 int getDay() const {return day;} 13 int getMaxDay() const; 14 bool isLeapYear() const { 15 return year%4==0 && year%100 != 0 || year%400==0; 16 } 17 void show() const; 18 19 int distance(const Date& date) const { 20 return totalDays-date.totalDays; 21 } 22 };
date.cpp:
1 #include "date.h" 2 #include<iostream> 3 #include<cstdlib> 4 using namespace std; 5 namespace { 6 const int DAYS_BEFIRE_MONTH[] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365}; 7 } 8 Date::Date(int year, int month, int day) :year(year), month(month), day(day) { 9 if (day <= 0 || day > getMaxDay()) { 10 cout << "Invalid date: "; 11 show(); 12 cout << endl; 13 exit(1); 14 } 15 int years = year - 1; 16 totalDays = years * 365 + years / 4 - years / 100 + years / 400 17 + DAYS_BEFIRE_MONTH[month - 1] + day; 18 if (isLeapYear() && month > 2) totalDays++; 19 } 20 int Date::getMaxDay()const { 21 if (isLeapYear() &&month == 2) 22 return 29; 23 else 24 return DAYS_BEFIRE_MONTH[month] - DAYS_BEFIRE_MONTH[month - 1]; 25 } 26 void Date::show()const { 27 cout << getYear() << "-" << getMonth() << "-" << getDay(); 28 }
account.h:
1 #pragma once 2 #include "date.h" 3 #include <string> 4 class SavingsAccount { 5 private: 6 std::string id; 7 double balance; 8 double rate; 9 Date lastDate; 10 double accumulation; 11 static double total; 12 13 void record(const Date &date, double amount, const std::string &desc); 14 15 void error(const std::string &msg) const; 16 17 double accumulate(const Date& date) const { 18 return accumulation+balance*date.distance(lastDate); 19 } 20 public: 21 SavingsAccount(const Date &date, const std::string &id, double rate); 22 const std::string &getId() const {return id;} 23 double getBalance() const {return balance;} 24 double getRate() const {return rate;} 25 static double getTotal() {return total;} 26 27 void deposit(const Date &date, double amount, const std::string &desc); 28 29 void withdraw(const Date &date, double amount, const std::string &desc); 30 31 void settle(const Date &date); 32 33 void show() const; 34 };
account.cpp:
1 #include "account.h" 2 #include <cmath> 3 #include <iostream> 4 using namespace std; 5 double SavingsAccount::total = 0; 6 7 SavingsAccount::SavingsAccount(const Date &date, const string &id, double rate) 8 : id(id), balance(0), rate(rate), lastDate(date), accumulation(0) { 9 date.show(); 10 cout << "\t#" << id << "created" << endl; 11 } 12 13 void SavingsAccount::record (const Date &date, double amount, const string &desc) { 14 accumulation = accumulate(date); 15 lastDate = date; 16 amount = floor(amount*100 + 0.5)/100; 17 balance += amount; 18 total += amount; 19 date.show(); 20 cout << "\t#" << id << "\t" << amount << "\t" << balance << "\t" << desc << endl; 21 } 22 23 void SavingsAccount::error(const string &msg) const { 24 cout << "Error(#"<<id<<"): " << msg << endl; 25 } 26 27 void SavingsAccount::deposit(const Date &date, double amount, const string &desc) { 28 record(date, amount, desc); 29 } 30 31 void SavingsAccount::withdraw(const Date &date, double amount, const string &desc) { 32 if(amount > getBalance()) 33 error("not enough money"); 34 else 35 record(date, -amount, desc); 36 } 37 38 void SavingsAccount::settle(const Date &date) { 39 double interest = accumulate(date)*rate 40 / date.distance(Date(date.getYear()-1, 1, 1)); 41 if(interest != 0) 42 record(date, interest, "interest"); 43 accumulation = 0; 44 } 45 46 void SavingsAccount::show() const { 47 cout << id << "\tBalance: " << balance; 48 }
6_25.cpp:
1 #include"account.h" 2 #include<iostream> 3 using namespace std; 4 int main() { 5 Date date{ 2008,11,1 }; 6 SavingsAccount accounts[] = { 7 SavingsAccount(date,"03755217",0.015), 8 SavingsAccount(date,"02342342",0.015) 9 }; 10 const int n = sizeof(accounts) / sizeof(SavingsAccount); 11 accounts[0].deposit(Date(2008, 11, 5), 5000, "salary"); 12 accounts[1].deposit(Date(2008, 11, 25), 10000, "sell stock 0323"); 13 14 accounts[0].deposit(Date(2008, 12, 5), 5500, "salary"); 15 accounts[1].withdraw(Date(2008, 12, 20), 4000, "buy a laptop"); 16 17 cout << endl; 18 for (int i = 0; i < n; i++) { 19 accounts[i].settle(Date(2009, 1, 1)); 20 accounts[i].show(); 21 cout << endl; 22 } 23 cout << "Total: " << SavingsAccount::getTotal() << endl; 24 return 0; 25 }
实验截图:
上面的程序增加了Date类,把对日期的表示均替换成了Date类型,输出效果比原来相比要直观的多。此外,本例广泛应用了字符串,这样在银行账号中可以出现字母,而且为每笔账目增加了说明文字,使得程序输出的信息更加丰富。