Vue的浮点型乘除法无法精确计算

Posted on 2021-09-06 17:12 jiaoqing。阅读(55) 评论(0) 编辑收藏举报

常见例子

// 加法
0.1 + 0.2 = 0.30000000000000004
0.1 + 0.7 = 0.7999999999999999
0.2 + 0.4 = 0.6000000000000001
 
// 减法
0.3 - 0.2 = 0.09999999999999998
1.5 - 1.2 = 0.30000000000000004
 
// 乘法
0.8 * 3 = 2.4000000000000004
19.9 * 100 = 1989.9999999999998
 
// 除法
0.3 / 0.1 = 2.9999999999999996
0.69 / 10 = 0.06899999999999999
 
// 比较
0.1 + 0.2 === 0.3 // false
(0.3 - 0.2) === (0.2 - 0.1) // false

解决方法

加

Vue.prototype.NumberAdd = function(arg1, arg2) {
    var r1, r2, m, n;
    try {
        r1 = arg1.toString().split(".")[1].length
    } catch (e) {
        r1 = 0
    }
    try {
        r2 = arg2.toString().split(".")[1].length
    } catch (e) { 
        r2 = 0 
    } 
    m = Math.pow(10, Math.max(r1, r2))
    n = (r1 >= r2) ? r1 : r2;
    return ((arg1 * m + arg2 * m) / m).toFixed(n);
}

减

Vue.prototype.NumberSub = function(arg1, arg2) {
    var re1, re2, m, n;
    try {
        re1 = arg1.toString().split(".")[1].length;
    } catch (e) {
    re1 = 0;
    }
    try {
        re2 = arg2.toString().split(".")[1].length;
    } catch (e) {
        re2 = 0;
    }
    m = Math.pow(10, Math.max(re1, re2)); 
    n = (re1 >= re2) ? re1 : re2;
    return ((arg1 * m - arg2 * m) / m).toFixed(n);
}

3.乘

Vue.prototype.NumberMul = function(arg1, arg2) {
    var m = 0;
    var s1 = arg1.toString();
    var s2 = arg2.toString();
    try {
        m += s1.split(".")[1].length;
    } catch (e) {}
    try {
        m += s2.split(".")[1].length;
    } catch (e) {}
 
    return Number(s1.replace(".", "")) * Number(s2.replace(".", "")) / Math.pow(10, m);
}

// 除数，被除数， 保留的小数点后的位数
Vue.prototype.NumberDiv = function (arg1,arg2,digit){
    var t1=0,t2=0,r1,r2;
    try{t1=arg1.toString().split(".")[1].length}catch(e){}
    try{t2=arg2.toString().split(".")[1].length}catch(e){}
    r1=Number(arg1.toString().replace(".",""))
    r2=Number(arg2.toString().replace(".",""))
    //获取小数点后的计算值
   var result= ((r1/r2)*Math.pow(10,t2-t1)).toString()
    var result2=result.split(".")[1];
    result2=result2.substring(0,digit>result2.length?result2.length:digit);
 
    return Number(result.split(".")[0]+"."+result2);
}

转载：https://blog.csdn.net/qq_32900003/article/details/112833795