POJ 3982 序列 塔尔苏斯问题解决

而且还加入了大量的主题，直接或模板Java我们能够在水。

除了循环33它的时间，计算A99它是第几，输出准确回答。

#include <stdio.h>
#include <string>
#include <algorithm>
using std::string;

const int MAX_B = 5120;
char buf[MAX_B];
int id = 0, len = 0;

inline char getFromBuf()
{
	if (id >= len)
	{
		len = fread(buf, 1, MAX_B, stdin);
		id = 0;
	}
	return buf[id++];
}

void getIntFromBuf(string &n)
{
	char a = getFromBuf();
	while ((a == ' ' || a == '\n') && len) a = getFromBuf();

	n.clear();
	while ((a != ' ' && a != '\n') && len)//老是写&&，错成||
	{
		n.push_back(a);
		a = getFromBuf();
	}
}

string operator+(string &a, string &b)
{
	string c;
	int N1 = (int)a.size(), N2 = (int)b.size();
	int carry = 0;
	for (int i = N1-1, j = N2-1; i>=0 || j>=0 || carry; i--, j--)
	{
		int an = i>=0? a[i]-'0' : 0;
		int bn = j>=0?
 b[j]-'0' : 0;
		int sum = an + bn + carry;
		carry = sum / 10;
		c.push_back(sum % 10 + '0');
	}
	reverse(c.begin(), c.end());
	return c;
}

int main()
{
	string a1, a2, a3;
	while (true)
	{
		getIntFromBuf(a1);
		if (len == 0) break;
		getIntFromBuf(a2);
		getIntFromBuf(a3);

		for (int i = 0; i < 33; i++)
		{
			string a = a2 + a3;
			a1 = a1 + a;
			if (i == 32) break;
			a2 = a1 + a;
			a3 = a3 + a1;
			a3 = a3 + a2;
		}
		puts(a1.c_str());
	}
	return 0;
}

版权声明：笔者心脏靖，景空间地址：http://blog.csdn.net/kenden23/，可能不会在未经作者同意转载。