cf 1741A A. Compare T-Shirt Sizes

Two T-shirt sizes are given: a and b. The T-shirt size is either a string M or a string consisting of several (possibly zero) characters X and one of the characters S or L.

For example, strings M, XXL, S, XXXXXXXS could be the size of some T-shirts. And the strings XM, LL, SX are not sizes.

The letter M stands for medium, S for small, L for large. The letter X refers to the degree of size (from eXtra). For example, XXL is extra-extra-large (bigger than XL, and smaller than XXXL).

You need to compare two given sizes of T-shirts a and b.

The T-shirts are compared as follows:

any small size (no matter how many letters X) is smaller than the medium size and any large size;
any large size (regardless of the number of letters X) is larger than the medium size and any small size;
the more letters X before S, the smaller the size;
the more letters X in front of L, the larger the size.
For example:

XXXS < XS
XXXL > XL
XL > M
XXL = XXL
XXXXXS < M
XL > XXXS
Input
The first line of the input contains a single integer t (1≤t≤104) — the number of test cases.

Each test case consists of one line, in which a and b T-shirt sizes are written. The lengths of the strings corresponding to the T-shirt sizes do not exceed 50. It is guaranteed that all sizes are correct.

Output
For each test case, print on a separate line the result of comparing a and b T-shirt sizes (lines “<”, “>” or “=” without quotes).

Example
inputCopy
6
XXXS XS
XXXL XL
XL M
XXL XXL
XXXXXS M
L M
outputCopy

#include<bits/stdc++.h>
using namespace std;
int main(void) {
	int n;
	cin >> n;
	string s[2];
	while (n--) {
		cin >> s[0] >> s[1];
		if (s[0][s[0].length() - 1] == s[1][s[1].length() - 1]) {
			if (s[0].length() > s[1].length())printf("%c\n", s[0][s[0].length() - 1] == 'S' ? '<' : '>');
			if (s[0].length() == s[1].length())cout << '=' << endl;
			if (s[0].length() < s[1].length())printf("%c\n", s[0][s[0].length() - 1] == 'S' ? '>' : '<');
		}
		else {
			if (s[0][s[0].length() - 1] > s[1][s[1].length() - 1]) {
				cout << '<'<<endl;
			}
			if (s[0][s[0].length() - 1] < s[1][s[1].length() - 1]) {
				cout << '>' << endl;
			}
		}
	}
}