java 实现一个简易计算器

Posted on 2016-11-22 21:56  醉银摩丶  阅读(6739)  评论(0编辑  收藏  举报
import java.util.Scanner;
public
class Test { public static void main(String[] args) { count(); } public static void count() { Scanner input1 = new Scanner(System.in); System.out.println("输入一个数"); double a = input1.nextDouble(); while (true) { Scanner input3 = new Scanner(System.in); System.out.println("提示:请输入您的操作"); System.out.println("+"); System.out.println("-"); System.out.println("*"); System.out.println("/"); System.out.println("F:退出"); String str = input3.nextLine(); char chr = str.toCharArray()[0]; switch (chr) { case '+': a = add(a); System.out.println("当前结果为:"+a); break; case '-': a = subtrace(a); System.out.println("当前结果为:"+a); break; case '*': a = ride(a); System.out.println("当前结果为:"+a); break; case '/': a = except(a); System.out.println("当前结果为:"+a); break; case 'F': System.out.println("结果:" + a); System.exit(-1); default: System.out.println("操作错误!"); break; } } } public static double add(double a) { Scanner input2 = new Scanner(System.in); System.out.println("输入一个数"); double b = input2.nextDouble(); return (a + b); } public static double subtrace(double a) { Scanner input2 = new Scanner(System.in); System.out.println("输入一个数"); double b = input2.nextDouble(); return (a - b); } public static double ride(double a) { Scanner input2 = new Scanner(System.in); System.out.println("输入一个数"); double b = input2.nextDouble(); return a * b; } public static double except(double a) { Scanner input2 = new Scanner(System.in); System.out.println("输入一个数"); double b = input2.nextDouble(); return a / b; } }