LeetCode: Letter Combinations of a Phone Number 解题报告

Letter Combinations of a Phone Number

Given a digit string, return all possible letter combinations that the number could represent.

A mapping of digit to letters (just like on the telephone buttons) is given below.



Input:Digit string "23"
Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].
Note:
Although the above answer is in lexicographical order, your answer could be in any order you want.

SOLUTION 1:

经典递归模板。

注意这一行不要写错了,根据当前的数字来取得可能的字母组合:

//get the possiable selections.
String s = map[digits.charAt(index) - '0'];

 1 public class Solution {
 2     String[] map = {"", "", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"};
 3     
 4     public List<String> letterCombinations(String digits) {
 5         List<String> ret = new ArrayList<String>();
 6         if (digits == null) {
 7             return ret;
 8         }
 9         
10         dfs(digits, new StringBuilder(), ret, 0);
11         return ret;
12     }
13     
14     public void dfs(String digits, StringBuilder sb, List<String> ret, int index) {
15         int len = digits.length();
16         if (index == len) {
17             ret.add(sb.toString());
18             return;
19         }
20         
21         // get the possiable selections.
22         String s = map[digits.charAt(index) - '0'];
23         for (int i = 0; i < s.length(); i++) {
24             sb.append(s.charAt(i));
25             dfs(digits, sb, ret, index + 1);
26             sb.deleteCharAt(sb.length() - 1);
27         }
28     }
29     
30 }
View Code

GITHUB:

https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/combination/LetterCombinations.java

posted on 2014-12-03 20:14  Yu's Garden  阅读(1727)  评论(0编辑  收藏  举报

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