LeetCode: Letter Combinations of a Phone Number 解题报告
Letter Combinations of a Phone Number
Given a digit string, return all possible letter combinations that the number could represent.
A mapping of digit to letters (just like on the telephone buttons) is given below.
Input:Digit string "23"
Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].
Note:
Although the above answer is in lexicographical order, your answer could be in any order you want.
SOLUTION 1:
经典递归模板。
注意这一行不要写错了,根据当前的数字来取得可能的字母组合:
//get the possiable selections.
String s = map[digits.charAt(index) - '0'];
1 public class Solution { 2 String[] map = {"", "", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"}; 3 4 public List<String> letterCombinations(String digits) { 5 List<String> ret = new ArrayList<String>(); 6 if (digits == null) { 7 return ret; 8 } 9 10 dfs(digits, new StringBuilder(), ret, 0); 11 return ret; 12 } 13 14 public void dfs(String digits, StringBuilder sb, List<String> ret, int index) { 15 int len = digits.length(); 16 if (index == len) { 17 ret.add(sb.toString()); 18 return; 19 } 20 21 // get the possiable selections. 22 String s = map[digits.charAt(index) - '0']; 23 for (int i = 0; i < s.length(); i++) { 24 sb.append(s.charAt(i)); 25 dfs(digits, sb, ret, index + 1); 26 sb.deleteCharAt(sb.length() - 1); 27 } 28 } 29 30 }
GITHUB:
https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/combination/LetterCombinations.java
posted on 2014-12-03 20:14 Yu's Garden 阅读(1727) 评论(0) 编辑 收藏 举报