根据一位网友的代码修改了一下
用服务器端的方法：
在页面上放一个gridview控件，配置好数据源，编辑列，添加一个模版列，再编辑模版，放入一个checkbox控件。代码如下：
<body> <form id="form1" runat="server"> <asp:ScriptManager ID="ScriptManager1" runat="server"/> <div> <asp:UpdatePanel ID="UpdatePanel1" runat="server"> <ContentTemplate> <asp:GridView ID="GridView1" runat="server"> <Columns> <asp:TemplateField> <HeaderTemplate> <asp:CheckBox ID="chkAll" runat="server" OnCheckedChanged="chkAll_CheckedChanged" AutoPostBack="True" /> </HeaderTemplate> <ItemTemplate> <asp:CheckBox ID="chkItem" runat="server" /> </ItemTemplate> </asp:TemplateField> </Columns> </asp:GridView> </ContentTemplate> </asp:UpdatePanel> </div> </form></body>后台cs代码：
using System.Web.UI;using System.Web.UI.WebControls;using System.Web.UI.WebControls.WebParts;using System.Web.UI.HtmlControls;using System.Data.SqlClient;public partial class Default3 : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack) { string conStr = "server=192.168.0.118;database=Northwind;Uid=sa;pwd="; string sql = "select * from Region"; SqlConnection con = new SqlConnection(conStr); SqlDataAdapter sda = new SqlDataAdapter(sql, con); DataSet ds = new DataSet(); sda.Fill(ds); this.GridView1.DataSource = ds; this.GridView1.DataBind(); sda.Dispose(); con.Close();
} } protected void chkAll_CheckedChanged(object sender, EventArgs e) { for (int i = 0; i < this.GridView1.Rows.Count; i++) { ((CheckBox)this.GridView1.Rows[i].FindControl("chkItem")).Checked = ((CheckBox)this.GridView1.HeaderRow.FindControl("chkAll")).Checked; } }
}本文转载自http://www.cnblogs.com/oec2003/archive/2007/11/09/954798.html，稍作修改~
