补题--I题

I.Letters

算法:前缀和+二分(lower_bound)

不开ll见祖宗

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
ll t,n,m;
const int N=2e5+10;
#define eps(a,b)  for(int i=a;i<=b;i++)
ll b[N],s[N];
int main()
{
    ios::sync_with_stdio(false);cin.tie();cout.tie();
    cin>>n>>m;
   eps(1,n){cin>>s[i];s[i]+=s[i-1];}
   eps(1,m)cin>>b[i];
   eps(1,m)
  {
    int pose=lower_bound(s+1,s+1+n,b[i])-s;
    //cout<<pose<<' ';
  //if(s[pose-1]>b[i])
     //ll l=0,r=a[i];
     cout<<pose<<' ';
     cout<<b[i]-s[pose-1]<<endl;
     //cout<<b[i]<<endl;
  }
    return 0;   
}