卡特兰数

题目链接:http://poj.org/problem?id=2084

Game of Connections
Time Limit: 1000MS   Memory Limit: 30000K
Total Submissions:9467   Accepted: 4639

Description

This is a small but ancient game. You are supposed to write down the numbers 1, 2, 3, . . . , 2n - 1, 2n consecutively in clockwise order on the ground to form a circle, and then, to draw some straight line segments to connect them into number pairs. Every number must be connected to exactly one another. 
And, no two segments are allowed to intersect. 
It's still a simple game, isn't it? But after you've written down the 2n numbers, can you tell me in how many different ways can you connect the numbers into pairs? Life is harder, right?

Input

Each line of the input file will be a single positive number n, except the last line, which is a number -1. 
You may assume that 1 <= n <= 100.

Output

For each n, print in a single line the number of ways to connect the 2n numbers into pairs.
 
思路:卡特兰数列,f[0] = 1, f[1] = 1, f[n] = f[n - 1] * (4 * n - 2) / (n + 1);大数 用java打表写即可。
 1 import java.util.*;
 2 import java.math.BigInteger;
 3 
 4 public class Main
 5 {
 6     public static void main(String [] args)
 7     {
 8         BigInteger [] a = new BigInteger [110];
 9         a[0] = BigInteger.ONE;
10         a[1] = BigInteger.valueOf(1);
11         for(int i = 2; i <= 100; i ++)
12         {
13             int x = 4 * i - 2, y = i + 1;
14             a[i] = a[i - 1].multiply(BigInteger.valueOf(x)).divide(BigInteger.valueOf(y));
15         }
16         Scanner cin = new Scanner (System.in);
17         int n;
18         while(true)
19         {
20             n = cin.nextInt();
21             if(n == -1)
22                 break;
23             System.out.println(a[n]);
24         }
25     }
26 }
View Code

 

posted @ 2019-07-27 18:31  缘未到  阅读(163)  评论(0编辑  收藏  举报