摘要: result = {} ids = {1,9,6,7}affs = {3,2,4,5,6}count =0for s in *ids result[s]=sfor p, v in pairs result count = count + 1print(count.."pppp")for s in * 阅读全文
posted @ 2022-06-24 16:59 改改改 阅读(39) 评论(0) 推荐(0) 编辑