python_2

import  math
C = 50
H = 30
value = []
#D = input().split(',')
D = [x for x in input().split(',')]
for d in D:
    value.append(str(int(round(math.sqrt(2*C*float(d)/H)))))
print(','.join(value))

输入一段序列,根据方程得出结果

注意点:

  1. 用list来接收和储存数据,这样对接下来的操作很是方便

  2.  D = [x for x in input().split(',')] 这种赋值列表的方法

  3. 强制类型转换的应用

  4. round()函数的用法,返回四舍五入值

--------------------------------------------------------------------------------------------------------------------------------------------------------

accept = input().split(',')
x = int(accept[0])
y = int(accept[1])
array = [[0 for i in range(y)] for j in range(x)]
print(array)
for i in range(x):
    for j in range(y):
        array[i][j] = i*j
print(array)

根据输入的数字生成二维数组

注意点:

  1. array的初始化定义

    array = [[0 for i in range(y)] for j in range(x)]  全0,x行y列

>>> array = [[0 for i in range(5)] for j in range(6)]
>>> array
[[0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]]
>>> array = [[i for i in range(5)] for j in range(6)]
>>> array
[[0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4]]
>>> array = [[j for i in range(5)] for j in range(6)]
>>> array
[[0, 0, 0, 0, 0], [1, 1, 1, 1, 1], [2, 2, 2, 2, 2], [3, 3, 3, 3, 3], [4, 4, 4, 4, 4], [5, 5, 5, 5, 5]]

理解:

  最里面的中括号是一行,外面的中括号是循环每一行

------------------------------------------------------------------------------------------------------------------------------------------------------

items = [x for x in input().split(',')]
items.sort()
print(','.join(items))

根据输入字符串的首字母进行排序

注意点:

  1. sort()函数和sorted()函数的区别

posted @ 2019-01-28 09:09  Freddy520  阅读(128)  评论(0编辑  收藏  举报