python+playwright 学习-81 page.expect_request()捕获网络请求

前言

page.expect_request() 可以捕获网页上发出去的请求，当有多个请求时，可以根据请求url，请求方式判断。

expect_request

官方文档示例

with page.expect_request("http://example.com/resource") as first:
    page.get_by_text("trigger request").click()
first_request = first.value

# or with a lambda
with page.expect_request(lambda request: request.url == "http://example.com" and request.method == "get") as second:
    page.get_by_text("trigger request").click()
second_request = second.value

expect_request 参数说明：
url_or_predicate : typing.Union[str, typing.Pattern[str], typing.Callable[["Request"], bool]]
请求URL字符串、正则表达式或接收Request参数的函数对象， 当通过上下文选项提供base_url并且传递的url是路径时，它将通过新的url（）构造函数进行合并。
timeout: typing.Optional[float] = None 设置超时时间，默认30秒，单位毫秒， 传递0以禁用超时。可以使用page.set_default_timeout（）方法更改默认值。

使用示例

示例代码

from playwright.sync_api import sync_playwright
# 上海悠悠 wx:283340479
# blog:https://www.cnblogs.com/yoyoketang/


with sync_playwright() as p:
    browser = p.chromium.launch(headless=False)
    context = browser.new_context()
    page = context.new_page()
    page.goto("http://127.0.0.1:8000/login.html")
    page.locator('#username').fill('yoyo')
    page.locator('#password').fill('******')

    with page.expect_request('http://127.0.0.1:8000/api/login') as first:
        page.locator('#loginBtn').click()

    first_request = first.value
    # 接口请求对象
    print(first_request.url)
    print(first_request.method)
    # 获取接口返回内容
    resp = first_request.response()
    print(resp.status)
    print(resp.json())

运行结果

http://127.0.0.1:8000/api/login
POST
400
{'message': '用户名或密码不正确'}