problem

1001 A+B Format (20)(20 point(s))
Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9
Sample Output

-999,991

anwser

#include <iostream> 
int main(){
	int a, b;
	int c;
	int end[10];
	std::cin>>a>>b;
	c = a+b;
	if (c==0) {
		std::cout<<"0";
		return 0;
	}
	if (c<0) {
		std::cout<<"-";
		c = -c;
	}
	int index = 0;
	while(c>0){
		end[index++] = c%1000;
		c/=1000;
	}
  	for(int i = index - 1; i >= 0; i--){
	  	if(i != index-1){
		  	if(end[i] == 0) 
		  		std::cout<<"000";
		    if(end[i] > 99)
		    	std::cout<<end[i];
		    else if(end[i] > 9){
		    	std::cout<<"0";
		    	std::cout<<end[i];
		    }
		    else if (end[i] > 0){
		    	std::cout<<"00";
		    	std::cout<<end[i];
			}
		}
		else 
			std::cout<<end[i]; 
	    if (i != 0)
	      std::cout<<",";
	}
	return 0;
}

experience

  • 边界条件要注意的
    • c ==0
  • 除首个数字外 end[i] == 0 的情况,并且要分类讨论
  • 首个数字不需要特殊处理
posted on 2018-07-01 19:14  yoyo_sincerely  阅读(201)  评论(0编辑  收藏  举报