软件设计模式————(解释器模式)

[实验任务一]:解释器模式

某机器人控制程序包含一些简单的英文指令,其文法规则如下:

expression ::= direction action distance | composite

composite ::= expression and expression

direction ::= ‘up’ | ‘down’ | ‘left’ | ‘right’

action ::= ‘move’ | ‘run’

distance ::= an integer //一个整数值

如输入:up move 5,则输出“向上移动5个单位”;输入:down run 10 and left move 20,则输出“向下移动10个单位再向左移动20个单位”。

实验要求:

1. 提交类图;

 

2. 提交源代码;

import java.util.Stack;
public abstract class AbstractNode {
public abstract String interpret();
}

public class ActionNode extends AbstractNode{
private String action;

public ActionNode(String action) {
this.action = action;
}

//动作(移动方式)表达式的解释操作
public String interpret() {
if (action.equalsIgnoreCase("move")) {
return "移动";
}
else if (action.equalsIgnoreCase("run")) {
return "快速移动";
}
else {
return "无效指令";
}
}
}


public class AndNode extends AbstractNode{
private AbstractNode left; //And的左表达式
private AbstractNode right; //And的右表达式

public AndNode(AbstractNode left, AbstractNode right) {
this.left = left;
this.right = right;
}

//And表达式解释操作
public String interpret() {
return left.interpret() + "再" + right.interpret();
}
}

public class DirectionNode extends AbstractNode{
private String direction;

public DirectionNode(String direction) {
this.direction = direction;
}

//方向表达式的解释操作
public String interpret() {
if (direction.equalsIgnoreCase("up")) {
return "向上";
}
else if (direction.equalsIgnoreCase("down")) {
return "向下";
}
else if (direction.equalsIgnoreCase("left")) {
return "向左";
}
else if (direction.equalsIgnoreCase("right")) {
return "向右";
}
else {
return "无效指令";
}
}
}

public class DistanceNode extends AbstractNode{
private String distance;

public DistanceNode(String distance) {
this.distance = distance;
}

//距离表达式的解释操作
public String interpret() {
return this.distance;
}
}

public class InstructionHandler {
private String instruction;
private AbstractNode node;
public void handle(String instruction) {
AbstractNode left = null, right = null;
AbstractNode direction = null, action = null, distance = null;
Stack stack = new Stack(); //声明一个栈对象用于存储抽象语法树
String[] words = instruction.split(" "); //以空格分隔指令字符串
for (int i = 0; i < words.length; i++) {
//本实例采用栈的方式来处理指令,如果遇到“and”,则将其后的三个单词作为三个终结符表达式连成一个简单句子SentenceNode作为“and”的右表达式,而将从栈顶弹出的表达式作为“and”的左表达式,最后将新的“and”表达式压入栈中。
if (words[i].equalsIgnoreCase("and")) {
left = (AbstractNode)stack.pop(); //弹出栈顶表达式作为左表达式
String word1= words[++i];
direction = new DirectionNode(word1);
String word2 = words[++i];
action = new ActionNode(word2);
String word3 = words[++i];
distance = new DistanceNode(word3);
right = new SentenceNode(direction,action,distance); //右表达式
stack.push(new AndNode(left,right)); //将新表达式压入栈中
}
//如果是从头开始进行解释,则将前三个单词组成一个简单句子SentenceNode并将该句子压入栈中
else {
String word1 = words[i];
direction = new DirectionNode(word1);
String word2 = words[++i];
action = new ActionNode(word2);
String word3 = words[++i];
distance = new DistanceNode(word3);
left = new SentenceNode(direction,action,distance);
stack.push(left); //将新表达式压入栈中
}
}
this.node = (AbstractNode)stack.pop(); //将全部表达式从栈中弹出
}

public String output() {
String result = node.interpret(); //解释表达式
return result;
}
}

public class SentenceNode extends AbstractNode{
private AbstractNode direction;
private AbstractNode action;
private AbstractNode distance;

public SentenceNode(AbstractNode direction,AbstractNode action,AbstractNode distance) {
this.direction = direction;
this.action = action;
this.distance = distance;
}

//简单句子的解释操作
public String interpret() {
return direction.interpret() + action.interpret() + distance.interpret();
}
}

public class Client {

public static void main(String[] args) {
// TODO Auto-generated method stub
String instruction1 = "up move 5 and down run 10 and left move 5";
String instruction2="down run 10 and left move 20";
InstructionHandler handler = new InstructionHandler();
handler.handle(instruction1);
String outString;
outString = handler.output();
System.out.println(outString);
handler.handle(instruction2);
outString = handler.output();
System.out.println(outString);
}

}

3. 注意编程规范。

posted @ 2024-11-21 15:22  财神给你送元宝  阅读(2)  评论(0编辑  收藏  举报