uva 10652 Board Wrapping
主要是凸包的应用;
1 #include <cstdio> 2 #include <cmath> 3 #include <cstring> 4 #include <algorithm> 5 #include <vector> 6 #define eps 1e-9 7 using namespace std; 8 const double pi = acos(-1); 9 10 int dcmp(double x) 11 { 12 return fabs(x) < eps ? 0 : (x > 0 ? 1 : -1); 13 } 14 15 struct Point 16 { 17 double x; 18 double y; 19 20 Point(double x = 0, double y = 0):x(x), y(y) {} 21 22 bool operator < (const Point& e) const 23 { 24 return dcmp(x - e.x) < 0 || (dcmp(x - e.x) == 0 && dcmp(y - e.y) < 0); 25 } 26 27 bool operator == (const Point& e) const 28 { 29 return dcmp(x - e.x) == 0 && dcmp(y - e.y) == 0; 30 } 31 }; 32 33 typedef Point Vector; 34 35 Vector operator + (Point A, Point B) 36 { 37 return Vector(A.x + B.x, A.y + B.y); 38 } 39 40 Vector operator - (Point A, Point B) 41 { 42 return Vector(A.x - B.x, A.y - B.y); 43 } 44 45 Vector operator * (Point A, double p) 46 { 47 return Vector(A.x * p, A.y * p); 48 } 49 50 Vector operator / (Point A, double p) 51 { 52 return Vector(A.x / p, A.y / p); 53 } 54 55 double cross(Point a,Point b){return a.x*b.y-a.y*b.x;} 56 Point rotate(Point a,double ang){return Point(a.x*cos(ang)-a.y*sin(ang),a.x*sin(ang)+a.y*cos(ang));} 57 int convexhull(Point *p,int n,Point *ch) 58 { 59 sort(p,p+n); 60 int m=0; 61 for(int i=0;i<n;i++) 62 { 63 while(m>1&&cross(ch[m-1]-ch[m-2],p[i]-ch[m-2])<=0)m--; 64 ch[m++]=p[i]; 65 } 66 int k=m; 67 for(int i=n-2;i>=0;i--) 68 { 69 while(m>k&&cross(ch[m-1]-ch[m-2],p[i]-ch[m-2])<=0)m--; 70 ch[m++]=p[i]; 71 } 72 if(n>1)m--; 73 return m; 74 } 75 Point p[2500],ch[2500]; 76 int main() 77 { 78 int t,n; 79 double alph,x,y,h,w,area1,area2; 80 scanf("%d",&t); 81 while(t--) 82 { 83 area1=area2=0; 84 scanf("%d",&n); 85 int pc=0; 86 for(int i=0;i<n;i++) 87 { 88 scanf("%lf%lf%lf%lf%lf",&x,&y,&w,&h,&alph); 89 Point o(x,y); 90 double ang=-(alph*pi/180); 91 p[pc++]=o+rotate(Point(-w/2,-h/2),ang); 92 p[pc++]=o+rotate(Point(w/2,-h/2),ang); 93 p[pc++]=o+rotate(Point(-w/2,h/2),ang); 94 p[pc++]=o+rotate(Point(w/2,h/2),ang); 95 area1+=w*h; 96 } 97 int m=convexhull(p,pc,ch); 98 for(int i=1;i<m;i++) 99 area2+=cross(ch[i]-ch[0],ch[i+1]-ch[0]); 100 area2/=2; 101 printf("%.1lf ",area1/area2*100); 102 puts("%"); 103 } 104 return 0; 105 }