获取一颗二叉树的中序后继节点
定义二叉树
二叉树除了有左右孩子节点外还有父母节点parent
代码
//获取中序后继节点
class CNode{
public:
int value;
CNode *left;
CNode *right;
CNode *parent;
CNode(int value):
value(value){
left = nullptr;
right = nullptr;
parent = nullptr;
}
};
CNode* CBTInit(){
CNode* head = new CNode(4);
head->left = new CNode(2);
head->left->parent = head;
head->right = new CNode(6);
head->right->parent = head;
head->left->left = new CNode(1);
head->left->left->parent = head->left;
head->left->right = new CNode(3);
head->left->right->parent = head->left;
head->right->left = new CNode(5);
head->right->left->parent = head->right;
head->right->right = new CNode(7);
head->right->right->parent = head->right;
return head;
}
CNode* getLastLeft(CNode* o){
if(o == nullptr){
return nullptr;
}
while(o->left != nullptr){
o = o->left;
}
return o;
}
CNode* getSuccessor(CNode *o){
if(o == nullptr){
return nullptr;
}
if(o->right != nullptr){
return getLastLeft(o->right);
}else{
while(o->parent != nullptr
&&
o == o->parent->right){
o = o->parent;
}
return o->parent;
}
}
主要是给自己看的,所以肯定会出现很多错误哈哈哈哈哈