dom4j解析xml

使用xpath解析指定节点数据,适用多层子节点遍历

1.依赖的jar包  

<dependency>
    <groupId>jaxen</groupId>
    <artifactId>jaxen</artifactId>
    <version>1.1.6</version>
</dependency>
<dependency>
    <groupId>dom4j</groupId>
    <artifactId>dom4j</artifactId>
    <version>1.6.1</version>
</dependency>

2.示例xml

<?xml version="1.0" encoding="UTF-8"?>
<Doc>
<a>
    <a1>a1</a1>
    <a2>a2</a2>
    <a3>
        <a31>龙妈</a31>
        <a32>卓跟</a32>
    </a3>
    <a3>
        <a31>穷</a31>
        <a32>小白</a32>
    </a3>
</a>
<a>
    <a1>a11</a1>
    <a2>a21</a2>
    <a3>
        <a31>龙妈和穷</a31>
        <a32>三龙齐飞</a32>
    </a3>
    <a3>
        <a31>铁王座</a31>
        <a32>穷</a32>
    </a3>
</a>
</Doc>

 

3.读取xml

  

 SAXReader reader = new SAXReader();
           Document doc =  reader.read("D:\\1.xml");
           //获取xml中节点名为a的所有节点,不能为根节点
           List<Element> aList = doc.selectNodes("//a");
           for (int i=0;i<aList.size();i++){
               Element a = aList.get(i);
               //selectSingleNode只适用于1:1
               //只会存在一个节点,如存在多个节点使用selectNodes
               Element a1 =  (Element)a.selectSingleNode("a1");
               Element a2 =  (Element)a.selectSingleNode("a2");
          
          //此处根据实际xml数据判断a1,a2节点是否=null,如果是必有节点,无需判断
          //if(a1==null) continue;

//根据业务逻辑取对应节点数据,只筛选a1=a11的数据 if (!"a11".equals(a1.getTextTrim())) { continue; } System.out.println("a2= "+a2.getTextTrim()); //多个子节点,使用此方法, List<Element> a3List = a.selectNodes("a3"); for (int j=0;j<a3List.size();j++){ Element a3 = a3List.get(j); Element a31 = (Element) a3.selectSingleNode("a31"); Element a32 = (Element) a3.selectSingleNode("a32"); System.out.println("a31= "+a31.getTextTrim()); System.out.println("a32= "+a32.getTextTrim()); } }

打印如下:

 

a2= a21
a31= 龙妈和穷
a32= 三龙齐飞
a31= 铁王座
a32= 穷

 

posted @ 2019-05-22 15:16  离骚不骚  阅读(179)  评论(0编辑  收藏  举报