pymysql模块

## pymysql的安装
pip3 install pymysql

## pymysql的链接、执行sql、关闭(游标)


import pymysql
user=input('用户名: ').strip()
pwd=input('密码: ').strip()

#链接
conn=pymysql.connect(
    host='localhost',
    user='root',
    database='db3',
    charset='utf8'
)


#游标
cursor=conn.cursor() #执行完毕返回的结果集默认以元组显示
#cursor=conn.cursor(cursor=pymysql.cursors.DictCursor)


#执行sql语句
sql='select * from userinfo where name="%s" and password="%s"' %(user,pwd) #注意%s需要加引号
print(sql)
res=cursor.execute(sql) #执行sql语句,返回sql查询成功的记录数目
print(res)

cursor.close()
conn.close()

if res:
    print('登录成功')
else:
    print('登录失败')
```

## execute()sql注入
注意:符号--会注释掉它之后的sql,正确的语法:--后至少有一个任意字符

根本原理:就根据程序的字符串拼接name='%s',我们输入一个_**xxx' -- haha**_,用我们输入的xxx加'在程序中拼接成一个判断条件name='_**xxx' -- haha**_'
```
最后那一个空格,在一条sql语句中如果遇到select * from t1 where id > 3 -- and name='alex';则--之后的条件被注释掉了

#1、sql注入之:用户存在,绕过密码
alex' -- 任意字符

#2、sql注入之:用户不存在,绕过用户与密码
xxx' or 1=1 -- 任意字符
```
绕过密码进行登陆
![](index_files/a46ff1a9-5da8-479d-b1fa-dfd9d526c9a7.png)
绕过用户和密码登陆
![](index_files/7bbe0232-716c-4244-ad8f-8959c9a4f526.png)

解决方法:
```
# 原来是我们对sql进行字符串拼接
# sql="select * from userinfo where name='%s' and password='%s'" %(user,pwd)
# print(sql)
# res=cursor.execute(sql)

#改写为(execute帮我们做字符串拼接,我们无需且一定不能再为%s加引号了)
sql="select * from userinfo where name=%s and password=%s" #!!!注意%s需要去掉引号,因为pymysql会自动为我们加上
res=cursor.execute(sql,[user,pwd]) #pymysql模块自动帮我们解决sql注入的问题,只要我们按照pymysql的规矩来。
```
示例代码:
```python
#!/usr/bin/env python3
# -*- coding:utf-8 -*-

import pymysql


user = input('>>:').strip()
pwd = input('>>:').strip()

conn = pymysql.connect(
    host = '127.0.0.1',
    port = 3306,
    user = 'root',
    db = 'db3',
    charset = 'utf8'
)

cursor = conn.cursor()

sql = 'select * from userinfo where name = %s and password = %s'
print(sql)
rows = cursor.execute(sql,[user,pwd])
print(rows)
cursor.close()
conn.close()

if rows:
    print('登陆成功')
else:
    print('登陆失败')
```

## pymysql 增、删、改conn.commit()
```python
#!/usr/bin/env python3
# -*- coding:utf-8 -*-

import pymysql

#建立链接
conn = pymysql.connect(
    host = '127.0.0.1',
    port = 3306,
    user = 'root',
    db = 'db3',
    charset = 'utf8'
)
# 拿游标
cursor = conn.cursor()
#执行sql语句
#增加
sql = 'insert into userinfo(name,password) values(%s,%s);'
# #删除
# # sql = 'delete from userinfo where id = 5;'
# #修改
# sql = 'update userinfo set name = "ALEX" where id = 1; '
print(sql)
# rows = cursor.execute(sql,('ab','123')) # 增加一条
rows = cursor.executemany(sql,[('ab','123'),('a','123'),('b','234')]) # 增加多条
print(cursor.lastrowid) # 获取最后一个插入的id

conn.commit() # 提交后才插入表格中
cursor.close()
conn.close()
```

## **查:fetchone,fetchmany,fetchall**
```python
#!/usr/bin/env python3
# -*- coding:utf-8 -*-

import pymysql

#建立链接
conn = pymysql.connect(
    host = '127.0.0.1',
    port = 3306,
    user = 'root',
    db = 'db3',
    charset = 'utf8'
)
# 拿游标
cursor = conn.cursor()
#执行sql
sql = 'select * from userinfo;'
rows = cursor.execute(sql)#执行sql语句,返回sql影响成功的行数rows,将结果放入一个集合,等待被查询

# cursor.scroll(2,mode='absolute') # 绝对位置移动
# cursor.scroll(2,mode='relative')# 相对位置移动
res1 = cursor.fetchone()
res2 = cursor.fetchone()
res3 = cursor.fetchone()
res4 = cursor.fetchone()
res5 = cursor.fetchmany(2)
res = cursor.fetchall()
print(res1)
print(res2)
print(res3)
print(res4)
print(res5)
print(res)
print('%s rows in set(0.00 sec)'%(rows))

 

posted @ 2018-07-04 15:17  游走在边缘的人  阅读(140)  评论(0编辑  收藏  举报