对0位压缩的 ipv6,进行补全

 
import socket,struct

ipv6 = "FF01::FF01:FF01"

前64位 = hex(struct.unpack("!Q",socket.inet_pton(socket.AF_INET6,ipv6)[:8])[0])[2:]
后64位 = hex(struct.unpack("!Q",socket.inet_pton(socket.AF_INET6,ipv6)[8:])[0])[2:]

 

l = [
    # "ABCD:EF01:2345:6789:DCAB:DD01:5623:1298",
    # "2001:DB8:0:23:8:800:200C:417A",

    # "::DB8:0:23:8:800:200C:417A",
    # "::DB8:23:8:800:200C:417A",
    # "::1:ABC:2",
    # "::1",

    # "1::2",
    # "FF01:ABCD::1101",
    # "2001:DB8::23:8:800:200C:417A",

    "DB8:0:23:8:800:200C:417A::",
    "1:2::",
    "1::",
]

for ip in l:
    if "::" not in ip:              # 没有0位压缩
        l1 = ip.split(":")
    elif "::" in ip:                # 0位压缩
        l1 = ip.split(":")
        if len(l1) > 8:             # 只压缩一个0,在前面或后面
            if l1[0] == "":
                l1.pop(0)
            elif l1[-1] == "":
                l1.pop(-1)
            for index,value in enumerate(l1):
                if value == "":
                    l1[index] = str(0)
        elif len(l1) == 8:          # 压缩一个0,在中间
            for index,value in enumerate(l1):
                if value == "":
                    l1[index] = str(0)
        elif len(l1) < 8:           # 压缩多个0
            s = "0"
            n = 8 - len(l1)
            for index,value in enumerate(l1):
                if value == "":
                    l1[index] = str(0)
                    for i in range(n):
                        l1.insert(index,"0")



    print(ip)
    # print(l1)
    print("==前64==",":".join(l1[:4]))
    print("==后64==",":".join(l1[-4:]))
代码实现,不准确,有漏项

 

posted on 2020-06-27 23:07  二十四岁半  阅读(968)  评论(0编辑  收藏  举报

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