[javascript]寄生组合式继承

子类需要继承超类的原型

function object(o){
                function f(){};
                f.prototype = o;
                return new f();
        }

            
function inheritPrototype( subType ,superType ,proto){
                var prototype = object( superType );
                prototype.constructor = subType;
                subType.prototype = prototype;
                
                for( p in proto ){
                    subType.prototype[p] = proto[p];
            }
        }

 

 创建互相继承的子类

function Root(){
            this.name = "Root";
}

var RootPrototype = {
            reWrite : function(){return "root_rewrite";},
            sayName : function(){console.log(this.name);}
};

for(p in RootPrototype){
            Root.prototype[p] = RootPrototype[p];
}


function Note_1(){
            this.name = "Note_1";
}

var Note_1Prototype = {
            reWrite : function(){return "note_1_rewrite";},
            note_1_own : function(){console.log("note_1_own");}
};

function Note_1_1(){
            this.name = "Note_1_1";
}

var Note_1_1Prototype = {
            reWrite : function(){return "note_1_1_rewrite";},
            note_1_1_own : function(){console.log("note_1_1_own");}
};

 

 继承

inheritPrototype( Note_1 ,Root.prototype ,Note_1Prototype);
inheritPrototype( Note_1_1 ,Note_1.prototype ,Note_1_1Prototype);

 

 测试

 

var _root = new Root();
var note_1 = new Note_1();
var note_1_1 = new Note_1_1();

console.log(_root);
console.log(note_1);
console.log(note_1_1);

_root.sayName();
note_1.sayName();
note_1_1.sayName();

note_1.note_1_own();
note_1_1.note_1_1_own();


console.log(note_1_1 instanceof Root);
console.log(note_1_1 instanceof String);
console.log(note_1 instanceof Root);

 

posted @ 2017-06-02 16:44  yiyide266  阅读(181)  评论(0编辑  收藏  举报