求循环小数

对于任意的真分数 N/M （ 0 < N < M ），均可以求出对应的小数。如果采用链表表示各个小数，对于循环节采用循环链表表示，则所有分数均可以表示为如下链表形式。

输入： N M

输出： 转换后的小数（不超过 50 ）

要求： 仅编写将分数转换为小数的函数 change( int n, int m, NODE * head ) 。 

测试输入关于“测试输入”的帮助期待的输出关于“期待的输出”的帮助时间限制关于“时间限制”的帮助内存限制关于“内存限制”的帮助额外进程关于“{$a} 个额外进程”的帮助
测试用例 1 以文本方式显示
  1. 1 8↵
 以文本方式显示
  1. 0.125↵
 1秒 64M 0
测试用例 2 以文本方式显示
  1. 29 33↵
 以文本方式显示
  1. 0.87878787878787878787878787878787878787878787878787↵
 1秒 64M 0
测试用例 3 以文本方式显示
  1. 7 18↵
 以文本方式显示
  1. 0.38888888888888888888888888888888888888888888888888↵
 1秒 64M 0
测试用例 4 以文本方式显示
  1. 2 7↵
 以文本方式显示
  1. 0.28571428571428571428571428571428571428571428571428↵
 1秒 64M 0

预设代码

前置代码

 1 /* PRESET CODE BEGIN - NEVER TOUCH CODE BELOW */
 2 
 3 #include <stdio.h>
 4 #include <stdlib.h>
 5 
 6 typedef struct node
 7 {   int         data;
 8     struct node * next;
 9 } NODE;
10 
11 void output( NODE * );
12 void change( int, int, NODE * );
13 
14 void output( NODE * head )
15 {   int k=0;
16 
17     printf("0.");
18     while ( head->next != NULL && k<50 )
19     {   printf("%d", head->next->data );
20         head = head->next;
21         k ++;
22     }
23     printf("\n");
24 }
25 
26 int main()
27 {   int n, m;
28     NODE * head;
29 
30     scanf("%d%d", &n, &m);
31     head = (NODE *)malloc( sizeof(NODE) );
32     head->next = NULL;
33     head->data = -1;
34     change( n, m, head );
35     output( head );
36     return 0;
37 }
38 
39 /* PRESET CODE END - NEVER TOUCH CODE ABOVE */

 

 

编写代码如下：

  1 /* PRESET CODE BEGIN - NEVER TOUCH CODE BELOW */
  2 
  3 #include <stdio.h>
  4 #include <stdlib.h>
  5 
  6 typedef struct node
  7 {
  8     int         data;
  9     struct node * next;
 10 } NODE;
 11 
 12 void output(NODE *);
 13 void change(int, int, NODE *);
 14 
 15 void output(NODE * head)
 16 {
 17     int k = 0;
 18 
 19     printf("0.");
 20     while (head->next != NULL && k<50)
 21     {
 22         printf("%d", head->next->data);
 23         head = head->next;
 24         k++;
 25     }
 26     printf("\n");
 27 }
 28 
 29 void change(int n, int m, struct node *head)
 30 {
 31     struct node *p, *left, *p1, *head_yu, *yu1;
 32     int chu;
 33     int shang;
 34     int i, k;
 35     int yu;
 36     chu = n;
 37     p = (NODE *)malloc(sizeof(struct node));
 38     left = (NODE *)malloc(sizeof(struct node));
 39     shang = chu * 10 / m;
 40     yu = chu * 10 % m;
 41     p->data = shang;
 42     head->next = p;
 43     p1 = p;
 44     if (yu == 0){
 45         p->next = NULL;
 46         return;
 47     }
 48     if (yu == chu){
 49         p->next = p;
 50         return;
 51     }
 52     left->data = chu;
 53     head_yu = yu1 = left;
 54     left->next = NULL;
 55     chu = yu;
 56     for (k = 1; k <= 49; k++){
 57         int count = 0;
 58         struct node *c;
 59         c = head_yu;
 60         while (c != NULL){
 61             if (c->data == chu){
 62                 count++;
 63                 break;
 64             }
 65             else{
 66                 c = c->next;
 67                 count++;
 68             }
 69         }
 70         if (c!=NULL&&c->data == chu){
 71             struct node *zhuan;
 72             int count2;
 73             zhuan = head;
 74             for (count2 = 1; count2 <= count; count2++)
 75                 zhuan = zhuan->next;
 76             p->next = zhuan;
 77             return;
 78         }
 79         p = (NODE *)malloc(sizeof(struct node));
 80         left = (NODE *)malloc(sizeof(struct node));
 81         shang = chu * 10 / m;
 82         yu = chu * 10 % m;
 83         p->data = shang;
 84         p1->next = p;
 85         p1 = p;
 86         if (yu == 0){
 87             p1->next = NULL;
 88             break;
 89         }
 90         left->data = chu;
 91         yu1->next = left;
 92         yu1 = left;
 93         left->next = NULL;
 94         chu = yu;
 95     }
 96 }
 97 
 98 int main()
 99 {
100     int n, m;
101     NODE * head;
102 
103     scanf("%d%d", &n, &m);
104     head = (NODE *)malloc(sizeof(NODE));
105     head->next = NULL;
106     head->data = -1;
107     change(n, m, head);
108     output(head);
109 
110     return 0;
111 }
112 
113 /* PRESET CODE END - NEVER TOUCH CODE ABOVE */

 

posted @ 2015-11-09 18:47  Daniel_Yi  阅读(872)  评论(0)  编辑  收藏  举报