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题解:

很显然会发现对于每种颜色分开处理这是一颗树

然后就是裸的lct

有个坑就是判断操作1 可能颜色改成跟原先一样的

代码:

#include <bits/stdc++.h>
using namespace std;
#define N 11000
#define M 15
int n,m,c,kk;
int cnt[M][N],v[N];
struct lct{
int data[N],fa[N];
int leftson[N],rightson[N];
int count2[N];
bool rev[N];
void down(int x)
{
    if (!rev[x]) return;
    swap(leftson[x],rightson[x]); rev[x]=0;
    rev[leftson[x]]^=1; rev[rightson[x]]^=1;
}
void updata(int x)
{
    down(x);
    count2[x]=count2[leftson[x]]+count2[rightson[x]]+1;
    data[x]=max(v[x],max(data[leftson[x]],data[rightson[x]]));    
}
bool pd(int x)
{
    int y=fa[x];
    if (leftson[y]!=x&&rightson[y]!=x) return false;
    else return (true);
}
void rotate(int x,int y)
{
    int father=fa[x];
    if (y==1)
    {
        rightson[father]=leftson[x];
        if (leftson[x]) fa[leftson[x]]=father;
    } else
    {
        leftson[father]=rightson[x];
        if (rightson[x]) fa[rightson[x]]=father;
    }
    fa[x]=fa[father];
    if (pd(father))
    {
        if (leftson[fa[x]]==father)
          leftson[fa[x]]=x;
        else rightson[fa[x]]=x;
    }
    fa[father]=x;
    if (y==1) leftson[x]=father;
    else rightson[x]=father;
    updata(father); updata(x);
}
void dfs(int x)
{
    if (pd(x)) dfs(fa[x]);
    down(x);
}
void splay(int x)
{
    dfs(x);
    int father=fa[x];
    while (pd(x))
    {
        if (!pd(father))
        {
            if (x==leftson[father]) rotate(x,2);
            else rotate(x,1);
        } else
        {
            if (father==leftson[fa[father]])
               if (x==leftson[father])
                 rotate(father,2),rotate(x,2);
               else rotate(x,1),rotate(x,2);
            else 
              if (x==rightson[father])
                rotate(father,1),rotate(x,1);
              else rotate(x,2),rotate(x,1);
        }
        father=fa[x];
    }
}
void access(int x)
{
    for (int y=0;x;y=x,x=fa[x])
      splay(x),rightson[x]=y,updata(x);
}
void makeroot(int x)
{
    access(x);
    splay(x);
    rev[x]^=1;
}
int findroot(int x)
{
    access(x);
    splay(x);
    while (leftson[x]) x=leftson[x];
    return x;
}
void split(int x,int y)
{
    makeroot(x);
    access(y);
    splay(y);
}
bool link(int x,int y)
{
    makeroot(x);
    if (findroot(y)!=x)
    { 
      fa[x]=y;
      return(1);
    }
    else return(0);
}
void cut(int x,int y)
{
    makeroot(x);
    if (findroot(y)==x&&fa[x]==y)
    {
        fa[x]=leftson[y]=0;
        updata(y);
    }
}
} num[M];
struct hash{
    #define  mo 5000007
    int cc=11000;
    struct {
        int a,b,c;
    }f[mo+1000];
    void push(int x,int y,int z)
    {
        int tmp=(cc*x+y)%mo;
        while (f[tmp].a) tmp=tmp%mo+1;
        f[tmp].a=x; f[tmp].b=y; f[tmp].c=z;
    }
    int find(int x,int y)
    {
        int tmp=(cc*x+y)%mo;
        while (f[tmp].a&&(!(f[tmp].a==x&&f[tmp].b==y))) tmp=tmp%mo+1;
        if (f[tmp].a==x&&f[tmp].b==y) return(tmp);
        else return(-1);
    }
}hash;
int main()
{
    freopen("network.in","r",stdin);
    freopen("network.out","w",stdout);
    cin>>n>>m>>c>>kk;
    for (int i=1;i<=n;i++)
      cin>>v[i];
    for (int i=1;i<=m;i++)
    {
        int c,d,e;
        cin>>c>>d>>e;
        hash.push(c,d,e); hash.push(d,c,e);
        cnt[e][c]++; cnt[e][d]++;
        num[e].link(c,d);
    }
    int k,x,y,z;
    for (int i=1;i<=kk;i++)
    {
        cin>>k;
        if (k==0)
        {
            cin>>x>>y;
            for (int i=0;i<c;i++)
            {
                num[i].access(x);
                num[i].splay(x);
                v[x]=y;
                num[i].updata(x);
            }
        }
        if (k==1)
        {
            cin>>x>>y>>z;
            int tmp=hash.find(x,y),tmp2=hash.find(y,x),tmp3=hash.f[tmp].c;
            if (tmp==-1) cout<<"No such edge."<<endl; else
            if (tmp3==z) cout<<"Success."<<endl; else
             if ((cnt[z][x]==2||cnt[z][y]==2)) cout<<"Error 1."<<endl; else
             if (num[z].link(x,y))
             {
                 num[tmp3].cut(x,y);
                 hash.f[tmp].c=z; hash.f[tmp2].c=z;
                 cnt[tmp3][x]--; cnt[tmp3][y]--;
                 cnt[z][x]++; cnt[z][y]++;
                 cout<<"Success."<<endl;
            } else cout<<"Error 2."<<endl;
        }
        if (k==2)
        {
            cin>>z>>x>>y;
            num[z].makeroot(x);
            if (num[z].findroot(y)==x)
            {
              num[z].split(x,y);
              cout<<num[z].data[y]<<endl;;
            } else cout<<-1<<endl;
        }
    }
    return 0;
}

 

posted @ 2018-03-14 13:14  尹吴潇  阅读(196)  评论(0编辑  收藏  举报