poj 2155（未完成）

线段树套线段树模板题

链接：http://poj.org/problem?id=2155

题解：

代码：

#include <bits/stdc++.h>
using namespace std;
int n,m,k;
char c;
#define maxn 1111
#define mid (p[x].h+p[x].t)/2
struct xds
{
    int h,t;
    struct re
    {
        int h,t,x,rev;
    }p[maxn*4];
    void down(int x)
    {
        if (!p[x].rev) return;
        if (p[x].h!=p[x].t)
        {
            p[x*2].rev^=1; p[x*2+1].rev^=1;
        } else
        {
            p[x].x^=1;
        }
        p[x].rev=0;
    }
    void build2(int x,int h,int t)
    {
        p[x].h=h; p[x].t=t; p[x].x=p[x].rev=0;
        if (h==t) return;
        build2(x*2,h,mid); build2(x*2+1,mid+1,t); 
    }
    void change2(int x,int h,int t)
    {
        down(x);
        if (p[x].h>t||p[x].t<h) return;
        if (h<=p[x].h&&p[x].t<=t)
        {
            p[x].rev^=1; down(x); return;
        }
        change2(x*2,h,t); change2(x*2+1,h,t); 
    }
    int query2(int x,int goal)
    {
        down(x);
        if (p[x].h==p[x].t) return(p[x].x);
        if (goal>mid) return(query2(x*2+1,goal));
        else return(query2(x*2,goal));
    }
}p[maxn*4];
void build1(int x,int h,int t,int m)
{
    p[x].h=h; p[x].t=t;
    p[x].build2(1,1,m);
    if (h==t) return;
    build1(x*2,h,mid,m); build1(x*2+1,mid+1,t,m);
} 
void change1(int x,int x1,int x2,int y1,int y2)
{
    if (p[x].h>x2||p[x].t<x1) return;
    if (x1<=p[x].h&&p[x].t<=x2)
    {
        p[x].change2(1,y1,y2); return;
    }
    change1(x*2,x1,x2,y1,y2); change1(x*2+1,x1,x2,y1,y2);    
}
int  query1(int x,int a,int b)
{
    if (p[x].h==p[x].t)
    {
        return(p[x].query2(1,b));
    }
    if (a>mid) return(query1(x*2+1,a,b));
    else return(query1(x*2,a,b));
}
int main()
{
    freopen("noip.in","r",stdin);
    freopen("noip.out","w",stdout); 
    cin>>k; int a1,b1,a2,b2;
    for (int o=1;o<=k;o++)
    {
        cin>>n>>m;
        build1(1,1,n,n);
        for (int i=1;i<=m;i++)
        {
            cin>>c;
            if (c=='C')
            {
                cin>>a1>>b1>>a2>>b2;
                change1(1,a1,a2,b1,b2);
            }
            if (c=='Q')
            {
                cin>>a1>>b1;
                cout<<query1(1,a1,b1);
            }
        }
    }
}