\begin{align*}
&\lim_{x\to0^+}\cot x(\frac{1}{\sin x}-\frac{1}{x})\\
=&\lim_{x\to0^+}\frac{x-\sin x}{x\sin x\tan x}\\
=&\lim_{x\to0^+}\frac{\frac{1}{3!}x^3+o(x^3)}{x^3}\cos x\\
=&\frac{1}{6}
\end{align*}
posted on 2015-09-10 11:47 Marlinhz 阅读(161) 评论(2) 编辑 收藏 举报