2016 ACM/ICPC Asia Regional Qingdao Online HDU5882

链接：http://acm.hdu.edu.cn/showproblem.php?pid=5882

解法：一个点必须出度和入度相同就满足题意，所以加上本身就是判断奇偶性

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#include<stdio.h> #include<math.h> #include<string.h> #include<stack> #include<set> #include<queue> #include<vector> #include<map> #include<iostream> #include<algorithm> #define LL long long using namespace std; int main() {     int n;     while(~scanf("%d",&n))     {         while(n--)         {             int m;             scanf("%d",&m);             if(m&1)             {                 cout<<"Balanced"<<endl;             }             else             {                 cout<<"Bad"<<endl;             }         }     }     return 0; }