Helvetic Coding Contest 2016 online mirror C1

Description

One particularly well-known fact about zombies is that they move and think terribly slowly. While we still don't know why their movements are so sluggish, the problem of laggy thinking has been recently resolved. It turns out that the reason is not (as previously suspected) any kind of brain defect – it's the opposite! Independent researchers confirmed that the nervous system of a zombie is highly complicated – it consists of nbrains (much like a cow has several stomachs). They are interconnected by brain connectors, which are veins capable of transmitting thoughts between brains. There are two important properties such a brain network should have to function properly:

It should be possible to exchange thoughts between any two pairs of brains (perhaps indirectly, through other brains).
There should be no redundant brain connectors, that is, removing any brain connector would make property 1 false.

If both properties are satisfied, we say that the nervous system is valid. Unfortunately (?), if the system is not valid, the zombie stops thinking and becomes (even more) dead. Your task is to analyze a given nervous system of a zombie and find out whether it is valid.

Input

The first line of the input contains two space-separated integers n and m (1 ≤ n, m ≤ 1000) denoting the number of brains (which are conveniently numbered from 1 to n) and the number of brain connectors in the nervous system, respectively. In the next m lines, descriptions of brain connectors follow. Every connector is given as a pair of brains a b it connects (1 ≤ a, b ≤ n, a ≠ b).

Output

The output consists of one line, containing either yes or no depending on whether the nervous system is valid.

Examples

input

output

no

input

output

yes
并查集判断环~

#include<stdio.h>
//#include<bits/stdc++.h>
#include<string.h>
#include<iostream>
#include<math.h>
//#include<map>
#include<sstream>
#include<set>
#include<queue>
#include<vector>
#include<algorithm>
#include<limits.h>
#define inf 0x3fffffff
using namespace std;
const double pi = acos(-1.);
#define maxn 100005
int fa[maxn];
bool ff[maxn];
int findd( int x )
{
    int k, j, r;
    r = x;
    while(r != fa[r])     //查找跟节点
        r = fa[r];      //找到跟节点，用r记录下
    k = x;
    while(k != r)             //非递归路径压缩操作
    {
        j = fa[k];         //用j暂存parent[k]的父节点
        fa[k] = r;        //parent[x]指向跟节点
        k = j;                    //k移到父节点
    }
    return r;         //返回根节点的值
}
int main()
{
    int u,v,x,y,flag = 1;
    memset(ff, false, sizeof(ff));
    int k = 0;
    int n,m;
    cin>>n>>m;
    for(int i = 1; i <=n; i++)
    {
        fa[i]=i;
    }
    for(int j=1;j<=m;j++)
    {
        cin>>u>>v;
        x = findd(u), y = findd(v);
        if(x!=y)
            fa[x]=y;
        else
            flag=0;
    }
    for(int i=1;i<=n;i++)
    {
        if(fa[i]==i)
        {
            k++;
        }
    }
    if(flag&&k<=1)
    {
        puts("yes");
    }
    else
    {
        puts("no");
    }
    return 0;
}