Weblogic10.3.6部署解决CXF webService 调用报错: “Cannot create a secure XMLInputFactory”

一,解决步骤

1.添加jar包

stax2-api-3.1.4.jar

woodstox-core-asl-4.4.1.jar

2.编写监听器

 1 package com.neusoft.cxf.listener;
 2 
 3 import java.util.Properties;
 4 
 5 import javax.servlet.ServletContextEvent;  
 6 import javax.servlet.ServletContextListener;  
 7   
 8 /** 
 9  * <p>Title: </p> 
10  * <p>Description: weblogic容器部署CXF服务优先加载指定jar包</p> 
11  * <p>Copyright:Copyright(c)2018</p> 
12  * <p>Company:东软集团</p> 
13  * @date 2018-04-25 
14  * @author duanml 
15  */  
16 public class CXFWeblogicListener implements ServletContextListener{  
17   
18       
19     public CXFWeblogicListener() {  
20     }  
21   
22     @Override  
23     public void contextDestroyed(ServletContextEvent arg0) {  
24           
25     }  
26   
27     @Override  
28     public void contextInitialized(ServletContextEvent arg0) {  
29         Properties props = System.getProperties();  
30         props.setProperty("org.apache.cxf.stax.allowInsecureParser", "1");
31     }  
32   
33 }

3.配置监听器

在web.xml下配置监听器

1 <!--  weblogic容器部署CXF服务监听器 -->  
2     <listener>  
3         <listener-class>com.neusoft.cxf.listener.CXFWeblogicListener</listener-class>  
4     </listener>

 

posted @ 2018-04-25 17:31  ╱、隐风っ九剑  阅读(285)  评论(0)  编辑  收藏  举报