HDU 1004 Let the Balloon Rise(map的使用)
传送门:
http://acm.hdu.edu.cn/showproblem.php?pid=1004
Let the Balloon Rise
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 143275 Accepted Submission(s): 56670
Problem Description
Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.
This year, they decide to leave this lovely job to you.
This year, they decide to leave this lovely job to you.
Input
Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.
A test case with N = 0 terminates the input and this test case is not to be processed.
A test case with N = 0 terminates the input and this test case is not to be processed.
Output
For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.
Sample Input
5
green
red
blue
red
red
3
pink
orange
pink
0
Sample Output
red
pink
Author
WU, Jiazhi
题目意思:
找颜色单词出现得最多的那个单词
分析:
map的用法
很方便呀
原来都没有怎么用过
第一次用
开心
好用
code:
#include<bits/stdc++.h> using namespace std; int main() { int n; while(cin>>n,n) { map<string,int> mm; map <string,int>::iterator it; string ch; for(int i=0;i<n;i++) { cin>>ch; mm[ch]++; } int sum=0; string str; for(it=mm.begin();it!=mm.end();it++) { if(it->second>sum) { sum=it->second; str=it->first; } } cout<<str<<endl; } return 0; }
心之所向,素履以往
分类:
ACM
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