Can you answer these queries
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Can you answer these queries I
1 #include <bits/stdc++.h> 2 using namespace std; 3 #define ls rt<<1 4 #define rs rt<<1|1 5 #define lson l, m, ls 6 #define rson m+1, r, rs 7 const int maxn = 50010; 8 9 int a[maxn], s[maxn]; 10 int pre[maxn<<2], post[maxn<<2], maxv[maxn<<2]; 11 12 void pushup(int l, int r, int rt){ 13 int m = (l+r)>>1; 14 pre[rt] = max(pre[ls], s[m]-s[l-1]+pre[rs]); 15 post[rt] = max(post[rs], s[r]-s[m]+post[ls]); 16 maxv[rt] = max(max(maxv[rs], maxv[ls]), pre[rs]+post[ls]); 17 } 18 19 void build(int l, int r, int rt){ 20 if(l==r) { 21 pre[rt] = post[rt] = maxv[rt] = a[l]; 22 return ; 23 } 24 int m = (l+r)>>1; 25 build(lson); 26 build(rson); 27 pushup(l, r, rt); 28 } 29 30 int query(int L, int R, int &ql, int &qr, int l, int r, int rt){ 31 if(L<=l && r<=R) { 32 ql = pre[rt]; 33 qr = post[rt]; 34 return maxv[rt]; 35 } 36 int m = (l+r)>>1; 37 if(R<=m) return query(L, R, ql, qr, lson); 38 if(L>m) return query(L, R, ql, qr, rson); 39 int a1, a2, b1, b2; 40 int s1 = query(L, R, a1, b1, lson); 41 int s2 = query(L, R, a2, b2, rson); 42 ql = max(a1, s[m] - s[max(l-1, L-1)] + a2); 43 qr = max(b2, s[min(r, R)] - s[m] + b1); 44 int ans = max(s1, s2); 45 ans = max(ans, b1+a2); 46 return ans; 47 } 48 49 int main() { 50 int n; 51 // freopen("in.txt", "r", stdin); 52 while(scanf("%d", &n)!=EOF){ 53 for(int i = 1; i <= n; i++) { 54 scanf("%d", &a[i]); 55 s[i] = s[i-1] + a[i]; 56 } 57 build(1, n, 1); 58 59 int t; 60 scanf("%d", &t); 61 while(t--){ 62 int a, b; 63 scanf("%d %d", &a, &b); 64 int x,y; 65 printf("%d\n", query(a, b, x, y, 1, n, 1)); 66 } 67 } 68 }
下面这个稍慢，不过代码更清晰
1 #include <bits/stdc++.h> 2 using namespace std; 3 #define ll long long 4 #define ls rt<<1 5 #define rs rt<<1|1 6 #define lson l, m, ls 7 #define rson m+1, r, rs 8 9 const int maxn = 50010; 10 int sum[maxn<<2], pre[maxn<<2], post[maxn<<2], maxv[maxn<<2]; 11 12 void pushup(int rt){ 13 sum[rt] = sum[ls] + sum[rs]; 14 pre[rt] = max(pre[ls], sum[ls] + pre[rs]); 15 post[rt] = max(post[rs], sum[rs] + post[ls]);; 16 maxv[rt] = max(max(maxv[ls], maxv[rs]), post[ls]+pre[rs]); 17 } 18 19 void build(int l, int r, int rt) { 20 if(l == r) { 21 scanf("%d", &sum[rt]); 22 pre[rt] = post[rt] = maxv[rt] = sum[rt]; 23 return; 24 } 25 int m = (l+r)>>1; 26 build(lson); 27 build(rson); 28 pushup(rt); 29 } 30 31 int query_sum(int L, int R, int l, int r, int rt) { 32 if(L <= l && r <= R) { 33 return sum[rt]; 34 } 35 int ans = 0; 36 int m = (l+r) >> 1; 37 if(L <= m) ans += query_sum(L, R, lson); 38 if(R > m) ans += query_sum(L, R, rson); 39 return ans; 40 } 41 int query_pre(int L, int R, int l, int r, int rt) { 42 if(L <= l && r <= R) { 43 return pre[rt]; 44 } 45 int m = (l+r)>>1; 46 if(R <= m) return query_pre(L, R, lson); 47 if(L > m) return query_pre(L, R, rson); 48 return max(query_pre(L, R, lson), query_sum(L, R, lson) + query_pre(L, R, rson)); 49 } 50 int query_post(int L, int R, int l, int r, int rt) { 51 if(L <= l && r <= R) { 52 return post[rt]; 53 } 54 int m = (l+r)>>1; 55 if(R <= m) return query_post(L, R, lson); 56 if(L > m) return query_post(L, R, rson); 57 return max(query_post(L, R, rson), query_sum(L, R, rson) + query_post(L, R, lson)); 58 } 59 int query_max(int L, int R, int l, int r, int rt) { 60 if(L <= l && r <= R) { 61 return maxv[rt]; 62 } 63 int m = (l+r)>>1; 64 if(R <= m) return query_max(L, R, lson); 65 if(L > m) return query_max(L, R, rson); 66 return max( max(query_max(L, R, lson), query_max(L, R, rson)), query_post(L, R, lson) + query_pre(L, R, rson)); 67 } 68 69 70 int main(){ 71 int n; 72 //freopen("in.txt", "r", stdin); 73 while(scanf("%d", &n) != EOF) { 74 build(1, n, 1); 75 int m; 76 scanf("%d", &m); 77 int L, R; 78 while(m--) { 79 scanf("%d %d", &L, &R); 80 printf("%d\n", query_max(L, R, 1, n, 1)); 81 } 82 } 83 }
Can you answer these queries III
1 #include <bits/stdc++.h> 2 using namespace std; 3 #define ls rt<<1 4 #define rs rt<<1|1 5 #define lson l, m, ls 6 #define rson m+1, r, rs 7 const int maxn = 50010; 8 9 int a[maxn]; 10 int pre[maxn<<2], post[maxn<<2], sum[maxn<<2], maxv[maxn<<2]; 11 12 void pushup(int l, int r, int rt) { 13 int m = (l+r)>>1; 14 sum[rt] = sum[ls] + sum[rs]; 15 pre[rt] = max(pre[ls], sum[ls]+pre[rs]); 16 post[rt] = max(post[rs], sum[rs]+post[ls]); 17 maxv[rt] = max(max(maxv[rs], maxv[ls]), pre[rs]+post[ls]); 18 } 19 20 void build(int l, int r, int rt){ 21 if(l==r) { 22 pre[rt] = post[rt] = sum[rt] = maxv[rt] = a[l]; 23 return ; 24 } 25 int m = (l+r)>>1; 26 build(lson); 27 build(rson); 28 pushup(l, r, rt); 29 } 30 31 int query(int L, int R, int &ql, int &qr, int l, int r, int rt){ 32 if(L<=l && r<=R) { 33 ql = pre[rt]; 34 qr = post[rt]; 35 return maxv[rt]; 36 } 37 int m = (l+r)>>1; 38 if(R<=m) return query(L, R, ql, qr, lson); 39 if(L>m) return query(L, R, ql, qr, rson); 40 int a1, a2, b1, b2; 41 int s1 = query(L, R, a1, b1, lson); 42 int s2 = query(L, R, a2, b2, rson); 43 ql = max(a1, sum[ls] + a2); 44 qr = max(b2, sum[rs] + b1); 45 int ans = max(s1, s2); 46 ans = max(ans, b1+a2); 47 return ans; 48 } 49 void update(int pos, int val, int l, int r, int rt) { 50 if(l == r) { 51 sum[rt] = pre[rt] = post[rt] = maxv[rt] = val; 52 return; 53 } 54 int m = (l+r)>>1; 55 if(pos<=m) update(pos, val, lson); 56 else update(pos, val, rson); 57 pushup(l, r, rt); 58 } 59 60 int main() { 61 int n; 62 // freopen("in.txt", "r", stdin); 63 while(scanf("%d", &n)!=EOF){ 64 for(int i = 1; i <= n; i++) { 65 scanf("%d", &a[i]); 66 } 67 build(1, n, 1); 68 int t; 69 scanf("%d", &t); 70 while(t--){ 71 int a, b; 72 int op; 73 scanf("%d", &op); 74 scanf("%d %d", &a, &b); 75 int x,y; 76 if(op == 1){ 77 printf("%d\n", query(a, b, x, y, 1, n, 1)); 78 } else { 79 update(a, b, 1, n, 1); 80 } 81 } 82 } 83 return 0; 84 }
Can you answer these queries IV
题目没有说Ｌ一定小于Ｒ， 神坑．．．
1 #include <bits/stdc++.h> 2 using namespace std; 3 #define ll long long 4 #define ls rt<<1 5 #define rs rt<<1|1 6 #define lson l, m, ls 7 #define rson m+1, r, rs 8 const int maxn = 100010; 9 10 ll sum[maxn<<2]; 11 12 void pushup(int rt) { 13 sum[rt] = sum[ls] + sum[rs]; 14 } 15 16 void build(int l, int r, int rt) { 17 if(l == r) { 18 scanf("%lld", &sum[rt]); 19 return; 20 } 21 int m = (l+r)>>1; 22 build(lson); 23 build(rson); 24 pushup(rt); 25 } 26 27 void update(int L, int R, int l, int r, int rt) { 28 if(r-l+1 == sum[rt]) return; 29 if(l == r) { 30 sum[rt] = sqrt(sum[rt]); 31 return; 32 } 33 int m = (l+r)>>1; 34 if(L<=m) update(L, R, lson); 35 if(R>m) update(L, R, rson); 36 pushup(rt); 37 } 38 ll query(int L, int R, int l, int r, int rt) { 39 if(L<=l && r<=R) return sum[rt]; 40 int m = (l+r)>>1; 41 ll ans = 0; 42 if(L <= m) ans+=query(L, R, lson); 43 if(R > m) ans+=query(L, R, rson); 44 return ans; 45 } 46 47 int main(){ 48 int n; 49 int kase = 0 ; 50 // freopen("in.txt", "r", stdin); 51 while(scanf("%d", &n)!=EOF) { 52 build(1, n, 1); 53 int L, R, op; 54 int m; 55 scanf("%d", &m); 56 printf("Case #%d:\n", ++kase); 57 while(m--) { 58 scanf("%d %d %d", &op, &L, &R); 59 if(L > R) swap(L,R); 60 if(op) { 61 printf("%lld\n", query(L, R, 1, n, 1)); 62 } else { 63 update(L, R, 1, n, 1); 64 } 65 } 66 puts(""); 67 } 68 return 0; 69 }
Can you answer these queries V
终于过了...
1 #include <bits/stdc++.h> 2 using namespace std; 3 #define ll long long 4 #define ls rt<<1 5 #define rs rt<<1|1 6 #define lson l, m, ls 7 #define rson m+1, r, rs 8 9 const int maxn = 10010; 10 int sum[maxn<<2], pre[maxn<<2], post[maxn<<2], maxv[maxn<<2]; 11 12 void pushup(int rt){ 13 sum[rt] = sum[ls] + sum[rs]; 14 pre[rt] = max(pre[ls], sum[ls] + pre[rs]); 15 post[rt] = max(post[rs], sum[rs] + post[ls]);; 16 maxv[rt] = max(max(maxv[ls], maxv[rs]), post[ls]+pre[rs]); 17 } 18 19 void build(int l, int r, int rt) { 20 if(l == r) { 21 scanf("%d", &sum[rt]); 22 pre[rt] = post[rt] = maxv[rt] = sum[rt]; 23 return; 24 } 25 int m = (l+r)>>1; 26 build(lson); 27 build(rson); 28 pushup(rt); 29 } 30 31 int query_sum(int L, int R, int l, int r, int rt) { 32 if(L > R) return 0; 33 if(L <= l && r <= R) { 34 return sum[rt]; 35 } 36 int ans = 0; 37 int m = (l+r) >> 1; 38 if(L <= m) ans += query_sum(L, R, lson); 39 if(R > m) ans += query_sum(L, R, rson); 40 return ans; 41 } 42 int query_pre(int L, int R, int l, int r, int rt) { 43 if(L > R) return 0; 44 if(L <= l && r <= R) { 45 return pre[rt]; 46 } 47 int m = (l+r)>>1; 48 if(R <= m) return query_pre(L, R, lson); 49 if(L > m) return query_pre(L, R, rson); 50 return max(query_pre(L, R, lson), query_sum(L, R, lson) + query_pre(L, R, rson)); 51 } 52 int query_post(int L, int R, int l, int r, int rt) { 53 if(L > R) return 0; 54 if(L <= l && r <= R) { 55 return post[rt]; 56 } 57 int m = (l+r)>>1; 58 if(R <= m) return query_post(L, R, lson); 59 if(L > m) return query_post(L, R, rson); 60 return max(query_post(L, R, rson), query_sum(L, R, rson) + query_post(L, R, lson)); 61 } 62 int query_max(int L, int R, int l, int r, int rt) { 63 if(L > R) return 0; 64 if(L <= l && r <= R) { 65 return maxv[rt]; 66 } 67 int m = (l+r)>>1; 68 if(R <= m) return query_max(L, R, lson); 69 if(L > m) return query_max(L, R, rson); 70 return max( max(query_max(L, R, lson), query_max(L, R, rson)), query_post(L, R, lson) + query_pre(L, R, rson)); 71 } 72 73 74 int main(){ 75 int n, t; 76 // freopen("in.txt", "r", stdin); 77 scanf("%d", &t); 78 while(t--) { 79 scanf("%d", &n); 80 build(1, n, 1); 81 int m; 82 scanf("%d", &m); 83 int x1, y1, x2, y2; 84 while(m--) { 85 scanf("%d %d %d %d", &x1, &y1, &x2, &y2); 86 int ans = 0; 87 if(y1 < x2) { 88 ans = query_post(x1, y1, 1, n, 1) + query_sum(y1+1, x2-1, 1, n, 1) + query_pre(x2, y2, 1, n, 1); 89 } else if(y1==y2) { 90 ans = max(query_max(x2, y2, 1, n, 1), query_post(x1, x2-1, 1, n, 1) + query_pre(x2, y2, 1, n, 1)); 91 } else if(x2 <= y1) { 92 ans = max( max(query_max(x2, y1, 1, n, 1), query_post(x1, x2-1, 1, n, 1) + query_sum(x2, y1, 1, n, 1) + query_pre(y1+1, y2, 1, n, 1)), 93 max(query_post(x1, x2-1, 1, n, 1) + query_pre(x2, y1, 1, n, 1), query_post(x2, y1, 1, n, 1) + query_pre(y1+1, y2, 1, n, 1)) ); 94 } 95 printf("%d\n", ans); 96 } 97 } 98 return 0; 99 }
