CodeForces 46DParking Lot线段树

 

 对于100的查询,用线段树搞。。

还是队友帮我调的,= =!错的很2b。同hotel搞法,只不过把他变长了,好处理头和为的停车位置。

#include <cstdio>
#include <cstring>
#include <algorithm>
#include <climits>
#include <string>
#include <iostream>
#include <map>
#include <cstdlib>
#include <list>
#include <set>
#include <queue>
#include <stack>
#include<math.h>
#include<vector>
using namespace std;

const int maxn = 111111;
int sum[maxn << 2]; int lsum[maxn << 2], rsum[maxn << 2], color[maxn << 2];
int q[maxn], q1[maxn];
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1

void up(int rt, int m)
{
    lsum[rt] = lsum[rt << 1];
    rsum[rt] = rsum[rt << 1 | 1];
    if (lsum[rt] == (m - (m >> 1))) lsum[rt] += lsum[rt << 1 | 1];
    if (rsum[rt] == (m >> 1)) rsum[rt] += rsum[rt << 1];
    sum[rt] = max(max(sum[rt << 1], sum[rt << 1 | 1]), rsum[rt << 1] + lsum[rt << 1 | 1]);
}

void down(int rt, int m)
{
    if (~color[rt]){
        color[rt << 1] = color[rt << 1 | 1] = color[rt];
        sum[rt << 1] = lsum[rt << 1] = rsum[rt << 1] = color[rt] ? 0 : (m - (m >> 1));
        sum[rt << 1 | 1] = lsum[rt << 1 | 1] = rsum[rt << 1 | 1] = color[rt] ? 0 : (m >> 1);
        color[rt] = -1;
    }
}

void build(int l, int r, int rt)
{
    color[rt] = -1; sum[rt] = lsum[rt] = rsum[rt] = r - l + 1;
    if (l == r) return;
    int mid = (l + r) >> 1;
    build(lson);
    build(rson);
}

void update(int L, int R, int add, int l, int r, int rt)
{
    if (L <= l&&r <= R){color[rt] = add;
        sum[rt] = lsum[rt] = rsum[rt] = color[rt] ? 0 : r - l + 1;
         return;
    }
    down(rt, r - l + 1);
    int mid = (l + r) >> 1;
    if (L <= mid) update(L, R, add, lson);
    if (R > mid) update(L, R, add, rson);
    up(rt, r - l + 1);
}

int ask(int key, int l, int r, int rt)
{
    if (l == r) return l;
    int mid = (l + r) >> 1;
    down(rt, r - l + 1);
    if (sum[rt << 1] >= key) return ask(key, lson);
    if (rsum[rt << 1] + lsum[rt << 1 | 1] >= key) return mid - rsum[rt << 1] + 1;
    return ask(key, rson);
}

int main()
{
    int n, a, b, c, d, m;
    scanf("%d%d%d", &n, &c, &d);
    build(1, c + n + d, 1);
    scanf("%d", &m);
    for (int i = 1; i <= m; i++){
        scanf("%d%d", &a, &b);
        if (a == 1){
            if (c + b + d > sum[1]){
                printf("-1\n"); continue;
            }
            int t = ask(c + b + d, 1, c + n + d, 1);
            printf("%d\n",t - 1);
            update(c + t, c + t + b - 1, 1, 1, c + n + d, 1);
            q[i] = t; q1[i] = b;
        }
        else{
            update(c + q[b], c + q[b] + q1[b] - 1, 0, 1, c + n + d, 1);
        }
    }
    return 0;

}

 

posted on 2014-08-21 23:04  一个西瓜  阅读(193)  评论(0编辑  收藏  举报

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