对字典排序
import scala.collection.mutable._
var grades=Map("Kim"->90,"EMily"->91);
var tmp1=grades.toSeq.sortBy(_._2)
var res=ListMap(tmp1:_*);
List[String,Int] 排序
val a = List(("a",2),("b",44),("c",20),("a",20),("a",1))
a.sortBy(x=>(x._2,x._1))
对对象排序
object _02Simple {
def main(args: Array[String]): Unit = {
val firstEmp: Emp = Emp(1, "michael", 10000.00)
val secondEmp: Emp = Emp(2, "james", 18000.00)
val thirdEmp = Emp(3, "shaun", 12000.00)
val empList = List(firstEmp, secondEmp, thirdEmp)
empList.sortBy(p => p.salary)(Ordering[Double]).foreach(println)
}
}
case class Emp(id: Int, name: String, salary: Double) {}
sortWith中传入【返回值为布尔型的函数】
List("Here", "are", "some", "sample", "strings", "to", "be", "sorted").sortWith{(a,b) =>
val cmp=a.size-b.size
(if (cmp==0) -a.compareTo(b) else cmp) > 0
}