leetcode 服务器环境
今天因为好奇扒取了 leetcode 服务器端的开发环境。
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方法：随便找个题，利用stdout 输出系统信息，如下：
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完整信息如下：
=== os information ===
Linux version 4.4.0-131-generic (buildd@lgw01-amd64-015) (gcc version 5.4.0 20160609 (Ubuntu 5.4.0-6ubuntu1~16.04.10) ) #157-Ubuntu SMP Thu Jul 12 15:51:36 UTC 2018
=== cpu infomation ===
processor : 0
vendor_id : GenuineIntel
cpu family : 6
model : 79
model name : Intel(R) Xeon(R) CPU E5-2697A v4 @ 2.60GHz
stepping : 1
microcode : 0x1
cpu MHz : 2599.996
cache size : 40960 KB
physical id : 0
siblings : 1
core id : 0
cpu cores : 1
apicid : 0
initial apicid : 0
fpu : yes
fpu_exception : yes
cpuid level : 13
wp : yes
flags : fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush mmx fxsr sse sse2 ss syscall nx pdpe1gb rdtscp lm constant_tsc arch_perfmon rep_good nopl eagerfpu pni pclmulqdq vmx ssse3 fma cx16 pcid sse4_1 sse4_2 x2apic movbe popcnt tsc_deadline_timer aes xsave avx f16c rdrand hypervisor lahf_lm abm 3dnowprefetch invpcid_single kaiser tpr_shadow vnmi flexpriority ept vpid fsgsbase tsc_adjust bmi1 hle avx2 smep bmi2 erms invpcid rtm rdseed adx smap xsaveopt
bugs : cpu_meltdown spectre_v1 spectre_v2 spec_store_bypass
bogomips : 5199.99
clflush size : 64
cache_alignment : 64
address sizes : 40 bits physical, 48 bits virtual
power management:
processor : 1
vendor_id : GenuineIntel
cpu family : 6
model : 79
model name : Intel(R) Xeon(R) CPU E5-2697A v4 @ 2.60GHz
stepping : 1
microcode : 0x1
cpu MHz : 2599.996
cache size : 40960 KB
physical id : 1
siblings : 1
core id : 0
cpu cores : 1
apicid : 1
initial apicid : 1
fpu : yes
fpu_exception : yes
cpuid level : 13
wp : yes
flags : fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush mmx fxsr sse sse2 ss syscall nx pdpe1gb rdtscp lm constant_tsc arch_perfmon rep_good nopl eagerfpu pni pclmulqdq vmx ssse3 fma cx16 pcid sse4_1 sse4_2 x2apic movbe popcnt tsc_deadline_timer aes xsave avx f16c rdrand hypervisor lahf_lm abm 3dnowprefetch invpcid_single kaiser tpr_shadow vnmi flexpriority ept vpid fsgsbase tsc_adjust bmi1 hle avx2 smep bmi2 erms invpcid rtm rdseed adx smap xsaveopt
bugs : cpu_meltdown spectre_v1 spectre_v2 spec_store_bypass
bogomips : 5199.99
clflush size : 64
cache_alignment : 64
address sizes : 40 bits physical, 48 bits virtual
power management:
=== memory information ===
MemTotal: 4046404 kB
MemFree: 1329068 kB
MemAvailable: 1974100 kB
Buffers: 159648 kB
Cached: 597080 kB
SwapCached: 29884 kB
Active: 1286924 kB
Inactive: 602876 kB
Active(anon): 657084 kB
Inactive(anon): 515256 kB
Active(file): 629840 kB
Inactive(file): 87620 kB
Unevictable: 3652 kB
Mlocked: 3652 kB
SwapTotal: 524284 kB
SwapFree: 3020 kB
Dirty: 12 kB
Writeback: 0 kB
AnonPages: 1107024 kB
Mapped: 44892 kB
Shmem: 36728 kB
Slab: 720068 kB
SReclaimable: 215152 kB
SUnreclaim: 504916 kB
KernelStack: 4848 kB
PageTables: 9472 kB
NFS_Unstable: 0 kB
Bounce: 0 kB
WritebackTmp: 0 kB
CommitLimit: 2547484 kB
Committed_AS: 2099816 kB
VmallocTotal: 34359738367 kB
VmallocUsed: 0 kB
VmallocChunk: 0 kB
HardwareCorrupted: 0 kB
AnonHugePages: 0 kB
CmaTotal: 0 kB
CmaFree: 0 kB
HugePages_Total: 0
HugePages_Free: 0
HugePages_Rsvd: 0
HugePages_Surp: 0
Hugepagesize: 2048 kB
DirectMap4k: 3686380 kB
DirectMap2M: 507904 kB
DirectMap1G: 0 kB -
源代码（获取系统信息的代码参考了)：
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
// mostly need to read the linux config files to get system info
// ---- get os info ---- //
void getOsInfo()
{
FILE *fp = fopen("/proc/version", "r");
if(NULL == fp)
printf("failed to open version\n");
char szTest[1000] = {0};
while(!feof(fp))
{
memset(szTest, 0, sizeof(szTest));
fgets(szTest, sizeof(szTest) - 1, fp); // leave out \n
printf("%s", szTest);
}
fclose(fp);
}
// ---- get cpu info ---- //
void getCpuInfo()
{
FILE *fp = fopen("/proc/cpuinfo", "r");
if(NULL == fp)
printf("failed to open cpuinfo\n");
char szTest[1000] = {0};
// read file line by line
while(!feof(fp))
{
memset(szTest, 0, sizeof(szTest));
fgets(szTest, sizeof(szTest) - 1, fp); // leave out \n
printf("%s", szTest);
}
fclose(fp);
}
// ---- get memory info ---- //
void getMemoryInfo()
{
FILE *fp = fopen("/proc/meminfo", "r");
if(NULL == fp)
printf("failed to open meminfo\n");
char szTest[1000] = {0};
while(!feof(fp))
{
memset(szTest, 0, sizeof(szTest));
fgets(szTest, sizeof(szTest) - 1, fp);
printf("%s", szTest);
}
fclose(fp);
}
// ---- get harddisk info ---- //
#include <fcntl.h>
#include <sys/ioctl.h>
#include <linux/hdreg.h>
void lin()
{
printf("=== os information ===\n");
getOsInfo();
printf("=== cpu infomation ===\n");
getCpuInfo();
printf("=== memory information ===\n");
getMemoryInfo();
}
class Solution {
public:
vector<vector<int>> threeSum(vector<int>& nums) {
lin();//选哪个题无所谓，调用一遍lin()就行，此处是选的3Sum这题
vector<vector<int>> t;
return t;
}
};
