C++11新特性之 std::forward(完美转发)
上篇博客对右值、右值引用都做了简要介绍。
我们也要时刻清醒,有时候右值会转为左值,左值会转为右值。
(或许“转换”二字用的不是非常准确)
假设我们要避免这样的转换呢?
我们须要一种方法能依照參数原来的类型转发到还有一个函数中。这才完美,我们称之为完美转发。
std::forward就能够保存參数的左值或右值特性。
由于是这样描写叙述的:
When used according to the following recipe in a function template, forwards the argument to another function with the value category it had when passed to the calling function.
样例:
template<class T>
void wrapper(T&& arg)
{
foo(std::forward<T>(arg)); // Forward a single argument.
}
If a call to wrapper() passes an rvalue std::string, then T is deduced to std::string (not std::string&, const std::string&, or std::string&&), and std::forward ensures that an rvalue reference is passed to foo.
If a call to wrapper() passes a const lvalue std::string, then T is deduced to const std::string&, and std::forward ensures that a const lvalue reference is passed to foo.
If a call to wrapper() passes a non-const lvalue std::string, then T is deduced to std::string&, and std::forward ensures that a non-const lvalue reference is passed to foo.
看一段站点上的代码(http://en.cppreference.com/w/cpp/utility/forward):
#include <iostream>
#include <memory>
#include <utility>
#include <array>
struct A {
A(int&& n) { std::cout << "rvalue overload, n=" << n << "\n"; }
A(int& n) { std::cout << "lvalue overload, n=" << n << "\n"; }
};
class B {
public:
template<class T1, class T2, class T3>
B(T1&& t1, T2&& t2, T3&& t3) :
a1_{std::forward<T1>(t1)},
a2_{std::forward<T2>(t2)},
a3_{std::forward<T3>(t3)}
{
}
private:
A a1_, a2_, a3_;
};
template<class T, class U>
std::unique_ptr<T> make_unique1(U&& u)
{
return std::unique_ptr<T>(new T(std::forward<U>(u)));
}
template<class T, class... U>
std::unique_ptr<T> make_unique(U&&... u)
{
return std::unique_ptr<T>(new T(std::forward<U>(u)...));
}
int main()
{
auto p1 = make_unique1<A>(2); // rvalue
int i = 1;
auto p2 = make_unique1<A>(i); // lvalue
std::cout << "B\n";
auto t = make_unique<B>(2, i, 3);
}
//输出:
rvalue overload, n=2
lvalue overload, n=1
B
rvalue overload, n=2
lvalue overload, n=1
rvalue overload, n=3
最后,记住:
无论是T&&、左值引用、右值引用,std::forward都会依照原来的类型完美转发。