摘要：
public class Prim { static int MAX = 65535; public static void prim(int[][] graph, int n){ char[] c = new char[]{'A','B','C','D','E','F','G','E','F'}; int[] lowcost = new int[n]; int[] mst = new int[n]; int i, j, min, minid, sum 阅读全文
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