sqlserver 触发器示例

代码如下:

1 --检查当前触发器是否已存在
2 IF exists(SELECT * FROM sysobjects WHERE xtype='TR' AND [name]='TR_INSERTUserInfo_LoginLog')
3 --存在即删除该触发器
4 DROP TRIGGER TR_INSERTUserInfo_LoginLog
5 go
6 --触发器创建在UserInfo表上 当对UserInfo表执行INSERT操作后 自动执行触发器中的SQL语句
7 CREATE TRIGGER TR_INSERTUserInfo_LoginLog
8 ON UserInfo
9 FOR INSERT
10 AS
11 BEGIN
12 --定义接受新建用户ID的参数
13 DECLARE @userID VARCHAR(50);
14 --查询INSERTED临时表获取新建用户ID
15 SELECT @userID=UserID FROM Inserted
16 --向用户登录日志表中添加新建用户登录日志
17 INSERT INTO LoginLog VALUES(@userID,getDate())
18 END
19 GO
20
21 IF EXISTS(SELECT * FROM sysobjects WHERE xtype='TR' AND [name]='TR_Update_UserInfo_ManagerLog')
22 DROP TRIGGER TR_Update_UserInfo_ManagerLog
23 GO
24 CREATE TRIGGER TR_Update_UserInfo_ManagerLog
25 ON UserInfo
26 FOR UPDATE
27 AS
28 --接受被更新用户信息的ID
29 DECLARE @userId INT
30 --接受更新前用户密码的变量
31 DECLARE @oldPwd VARCHAR(50)
32 --接受更新后用户密码的变量
33 DECLARE @newPwd VARCHAR(50)
34 --接受更新前用户邮件的变量
35 DECLARE @oldEmail VARCHAR(50)
36 --接受更新后用户邮件的变量
37 DECLARE @newEmail VARCHAR(50)
38 --从DELETED临时表中获取数据更新前用户数据
39 SELECT @userId=UserId,@oldPwd=password,@oldEmail=Email FROM Deleted
40 --从INSERTED临时表中获取数据更新后的用户数据
41 SELECT @newPwd=password,@newEmail=Email FROM Inserted
42 --向系统日志表中插入数据
43 INSERT INTO managerlog VALUES('修改ID为:['+CAST(@userId AS VARCHAR(5))+']用户信息:<br/>Password:{'+@oldPwd+'}-->Password:{'+@newPwd+'}<br/>Email:{'+@oldEmail+'}-->{'+@newEmail+'}',getDate())
44 Go
45
46
47 --创建当用户表插入新数据时,添加工资表对应记录的触发器
48 IF EXISTS(SELECT * FROM sysobjects WHERE [xtype]='TR' AND [name]='Insert_Emp_EmpPayment')
49 DROP TRIGGER Insert_Emp_EmpPayment
50 go
51 CREATE TRIGGER Insert_Emp_EmpPayment
52 ON Employee1
53 FOR INSERT
54 AS
55 DECLARE @empId INT
56 SELECT @empId=EmpId FROM Inserted
57 INSERT INTO EmpPayMent VALUES(@empId,800.00,null)
58 go
59
60 --创建当向工资表插入数据时,更新工资表中员工奖金
61 IF EXISTS(SELECT * FROM sysobjects WHERE [xtype]='TR' AND [name]='Insert_EmpPayment')
62 DROP TRIGGER Insert_EmpPayment
63 go
64 CREATE TRIGGER Insert_EmpPayment
65 ON EmpPayMent
66 FOR INSERT
67 AS
68 DECLARE @empId INT
69 SELECT @empId=EmpId FROM Inserted
70 UPDATE EmpPayMent SET Bonus=50.00 WHERE EmpID=@empId
71 go

posted @ 2011-05-04 10:49  KT野人  阅读(387)  评论(0编辑  收藏  举报