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easyui datagrid种编辑器combobox选择的值不显示解决方案

 

var combobox_json = [{
        "combobox_value" : "GDLB01",
        "combobox_name" : "选项1"
    }, {
        "combobox_value" : "GDLB02",
        "combobox_name" : "选项1"
    }, {
        "combobox_value" : "GDLB03",
        "combobox_name" : "选项3"
    }, {
        "combobox_value" : "GDLB04",
        "combobox_name" : "选项4"
    }, {
        "combobox_value" : "GDLB05",
        "combobox_name" : "选项5"
    }
];

$("#dg1").datagrid({
    idField : "id",
    //fitColumns: true,
    data : [{
            "id" : "id1",
            "combobox_value" : "GDLB011",
            "combobox_name" : "选项1"
        }, {
            "id" : "id2",
            "combobox_value" : "GDLB012",
            "combobox_name" : "选项2"
        }, {
            "id" : "id3",
            "combobox_value" : "GDLB013",
            "combobox_name" : "选项3"
        }, {
            "id" : "id4",
            "combobox_value" : "GDLB014",
            "combobox_name" : "选项4"
        }, {
            "id" : "id5",
            "combobox_value" : "GDLB015",
            "combobox_name" : "选项5"
        }
    ],
    queryParams : {},
    columns : [[{
                field : 'combobox_value',
                title : '工段',
                width : 150,
                editor : {
                    type : 'combobox',
                    options : {
                        valueField : "combobox_value",
                        textField : "combobox_name",
                        data : combobox_json

                    }
                },
                formatter : function (value, row, index) {
                    for (var i = 0; i < combobox_json.length; i++) {
                        if (combobox_json[i].combobox_value == value) {
                            return combobox_json[i].combobox_name;
                        }
                    }
                    return row["combobox_name"];
                }
            }
        ]]
});

 

 

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posted on 2016-11-30 17:15  一个草率的龙果果  阅读(5772)  评论(0编辑  收藏  举报

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