HOJ 3138 Discover's problem
http://acm.hit.edu.cn/hoj/problem/view?id=3138
HOJ 3138 Discover's problem
Source : HCPC FALL 2012 | |||
Time limit : 2 sec | Memory limit : 64 M |
Submitted : 38, Accepted : 13
We define X property of two array A[n] and B[n] as:
It’s guaranteed that all the integer in the input are not larger than 1000.
Write a program to calculate the X property of two array.
Input
First line give a number T . Then T cases follows. Each case occupy three lines. The first line is a number n which is the length of arrays. The second and third line each consisting of n positive integers indicate array A[n] and B[n].It’s guaranteed that all the integer in the input are not larger than 1000.
Output
Print the X property in a line for each input case.Sample Input
3
1
2
2
2
1 2
5 6
3
1 2 3
4 5 6
Sample Output
0
16
54
#include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; typedef long long ll; const int X = 1005; ll a[X],b[X]; ll ans; int n; int main(){ freopen("ain.txt","r",stdin); int ncase; cin>>ncase; while(ncase--){ cin >> n; ans = 0; ll x = 0,y = 0; for(int i=1;i<=n;i++){ scanf("%lld",&a[i]); x += a[i]*a[i]; } for(int i=1;i<=n;i++){ scanf("%lld",&b[i]); y += b[i]*b[i]; ans -= a[i]*b[i]; } cout<<-ans*ans+x*y<<endl; } return 0; }