矩阵乘法模板

#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<algorithm>
using namespace std;

const int inf = 0x3f3f3f3f;
const int N = 101;

int n, m; 
struct Matrix{
    int mat[N][N];
    Matrix(){
        memset(mat,0,sizeof(mat));    
    }
    void input(){
        for(int i = 0; i < m; i++)
            for(int j = 0; j < m; j++)
                scanf("%d",&mat[i][j] );
    }    
    void unit(){
        memset(mat,0,sizeof(mat));
        for(int i = 0; i < m; i++) mat[i][i] = 1;
    } 
    Matrix& operator = (const Matrix &a){
        memcpy( mat, a.mat, sizeof(a.mat));
        return *this;
    } 
    friend Matrix operator * (const Matrix &a, const Matrix &b){
        Matrix res; 
        for(int i = 0; i < m; i++)
            for(int k = 0; k < m; k++)
                if( a.mat[i][k] )
                    for(int j = 0; j < m; j++)
                        res.mat[i][j] += a.mat[i][k]*b.mat[k][j];
        return res;
    }
    friend bool operator == (const Matrix &a, const Matrix &b){
        for(int i = 0; i < m; i++)
            for(int j = 0; j < m; j++)
                if( a.mat[i][j] != b.mat[i][j] ) return false;
        return true;
    }  
    friend Matrix operator ^ (Matrix a,int k){
        Matrix res; res.unit();
        Matrix x; memcpy( x.mat, a.mat, sizeof(a.mat));
        while(k){
            if( k&1 ) res = res*x;
            x = x*x; k >>= 1;    
        }    
        return res;
    } 
};

int dis[N][N];
Matrix A[N];

void floyd(){
    for(int k = 0; k < n; k++)
    for(int i = 0; i < n; i++) 
    if( dis[i][k] != inf )
    for(int j = 0; j < n; j++)
    if( dis[i][j] > dis[i][k] + dis[k][j] )
    dis[i][j] = dis[i][k] + dis[k][j]; 
}
int main(){
    while( scanf("%d%d", &n,&m), n+m ){
        for(int i = 0; i < n; i++)
            A[i].input();
        memset(dis, 0x3f, sizeof(dis));
        for(int i = 0; i < n; i++)
            for(int j = 0; j < n; j++){
                Matrix t = A[i]*A[j];
                for(int k = 0; k < n; k++)
                    if( t == A[k] && (k!=i && k!=j) )//不明觉厉... 
                        dis[i][k] = 1;
            }
        floyd();
        
        int a, b, k;scanf("%d", &k);
        for(int i = 0; i < k; i++){
            scanf("%d%d",&a,&b);
            if( dis[a-1][b-1] == inf ) printf("Sorry\n");
            else     printf("%d\n", dis[a-1][b-1] );    
        }
        
    } 
    return 0;
}

 

posted @ 2013-04-22 22:48  yefeng1627  阅读(215)  评论(0编辑  收藏  举报

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