sql语句获得当日,当周,当月,当季,当年的日期

今天淘到宝了,收藏: http://www.bubuko.com/infodetail-1446425.html
话说有一文章表article,存储文章的添加文章的时间是add_time字段,该字段为int(5)类型的,现需要查询今天添加的文章总数并且按照时间从大到小排序,则查询语句如下:
02     
03    1    select * from `article` where date_format(from_UNIXTIME(`add_time`),%Y-%m-%d) = date_format(now(),%Y-%m-%d);
04    或者:
05     
06    1    select * from `article` where to_days(date_format(from_UNIXTIME(`add_time`),%Y-%m-%d)) = to_days(now());
07    假设以上表的add_time字段的存储类型是DATETIME类型或者TIMESTAMP类型,则查询语句也可按如下写法:
08     
09    查询今天的信息记录:
10     
11    1    select * from `article` where to_days(`add_time`) = to_days(now());
12    查询昨天的信息记录:
13     
14    1    select * from `article` where to_days(now()) – to_days(`add_time`) <= 1;
15    查询近7天的信息记录:
16     
17    1    select * from `article` where date_sub(curdate(), INTERVAL 7 DAY) <= date(`add_time`);
18    查询近30天的信息记录:
19     
20    1    select * from `article` where date_sub(curdate(), INTERVAL 30 DAY) <= date(`add_time`);
21    查询本月的信息记录:
22     
23    1    select * from `article` where date_format(`add_time`, ‘%Y%m) = date_format(curdate() , ‘%Y%m);
24    查询上一月的信息记录:
25     
26    1    select * from `article` where period_diff(date_format(now() , ‘%Y%m) , date_format(`add_time`, ‘%Y%m)) =1;
27    对上面的SQL语句中的几个函数做一下分析:
28     
291)to_days
30     
31    就像它的名字一样,它是将具体的某一个日期或时间字符串转换到某一天所对应的unix时间戳,如:
32     
33    01   mysql> select  to_days(2010-11-22 14:39:51);     
34    02    +--------------------------------+                                                       
35    03   | to_days(2010-11-22 14:39:51) |
36    04   +--------------------------------+
37    05   |                         734463 |
38    06   +--------------------------------+
39    07   
40    08   mysql> select  to_days(2010-11-23 14:39:51);
41    09   +--------------------------------+
42    10   | to_days(2010-11-23 14:39:51) |
43    11   +--------------------------------+
44    12   |                         734464 |
45    13   +--------------------------------+
46    可以看出22日与23日的差别就是,转换之后的数增加了1,这个粒度的查询是比较粗糙的,有时可能不能满足我们的查询要求,那么就需要使用细粒度的查询方法str_to_date函数了,下面将分析这个函数的用法。
47     
48    提醒:
49     
501)to_days() 不用于阳历出现(1582)前的值,原因是当日历改变时,遗失的日期不会被考虑在内。因此对于1582 年之前的日期(或许在其它地区为下一年 ), 该函数的结果实不可靠的。
51      
522)MySQL"日期和时间类型"中的规则是将日期中的二位数年份值转化为四位。因此对于1997-10-0797-10-07将被视为同样的日期:
53     
54    1    mysql> select to_days(1997-10-07), to_days(97-10-07);
55    2    
56    3    -> 729669, 729669
572)str_to_date
58     
59    这个函数可以把字符串时间完全的翻译过来,如:
60     
61    1    mysql> select str_to_date("2010-11-23 14:39:51",%Y-%m-%d %H:%i:%s);
62    2    
63    3    +--------------------------------------------------------+
64    4    | str_to_date("2010-11-23 14:39:51",%Y-%m-%d %H:%i:%s) |
65    5    +--------------------------------------------------------+
66    6    | 2010-11-23 14:39:51                                    |
67    7    +--------------------------------------------------------+
68    具体案例操作如下:
69     
70    1    select str_to_date(article.`add_time`,%Y-%m-%d %H:%i:%s)
71    2    from article
72    3    where str_to_date(article.`add_time`,%Y-%m-%d %H:%i:%s)>=2012-06-28 08:00:00 and str_to_date(article.`add_time`,%Y-%m-%d %H:%i:%s)<=2012-06-28 09:59:59;
查询
今天
select * from 表名 where to_days(时间字段名) = to_days(now());  
昨天
 
SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) – TO_DAYS( 时间字段名) <= 1  
7天
 
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)  
近30天
 
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名) 

本月
 
SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, ‘%Y%m’ ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m’ )  
上一月
 
SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m’ ) , date_format( 时间字段名, ‘%Y%m’ ) ) =1  
同时,再附上 一个 mysql官方的相关document

#查询本季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
#查询上季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
#查询本年数据
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
#查询上年数据
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
 
查询当前这周的数据 
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,%Y-%m-%d)) = YEARWEEK(now());
查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,%Y-%m-%d)) = YEARWEEK(now())-1;
查询当前月份的数据
select name,submittime from enterprise   where date_format(submittime,%Y-%m)=date_format(now(),%Y-%m)
查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查询上个月的数据
select name,submittime from enterprise   where date_format(submittime,%Y-%m)=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),%Y-%m)
select * from ` user ` where DATE_FORMAT(pudate,  %Y%m  ) = DATE_FORMAT(CURDATE(),  %Y%m  ) ;
select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,%y-%m-%d)) = WEEKOFYEAR(now())
select * 
from user 
where MONTH (FROM_UNIXTIME(pudate,  %y-%m-%d  )) = MONTH (now())
select * 
from [ user ] 
where YEAR (FROM_UNIXTIME(pudate,  %y-%m-%d  )) = YEAR (now())
and MONTH (FROM_UNIXTIME(pudate,  %y-%m-%d  )) = MONTH (now())
select * 
from [ user ] 
where pudate between 上月最后一天
and 下月第一天
where   date(regdate)   =   curdate();
select   *   from   test   where   year(regdate)=year(now())   and   month(regdate)=month(now())   and   day(regdate)=day(now())
SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30

 

sql语句获取今天、昨天、近7天、本周、上周、本月、上月、半年数据

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原文:http://www.cnblogs.com/xiaoqian1993/p/5260789.html

posted @ 2016-03-11 13:55  yeemi  阅读(1702)  评论(0编辑  收藏  举报